Showing string in formula and not as variable in lm fit

久未见 提交于 2019-11-27 09:49:16

How about eval(call("lm", sformula))?

lm(sformula)
#Call:
#lm(formula = sformula)

eval(call("lm", sformula))
#Call:
#lm(formula = "y~x")

Generally speaking there is a data argument for lm. Let's do:

mydata <- data.frame(y = y, x = x)
eval(call("lm", sformula, quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)

The above call() + eval() combination can be replaced by do.call():

do.call("lm", list(formula = sformula))
#Call:
#lm(formula = "y~x")

do.call("lm", list(formula = sformula, data = quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)
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