问题
I am dealing with big matrices and time to time my code ends with 'killed:9' message in my terminal. I'm working on Mac OSx.
A wise programmer tells me the problem in my code is liked to the stored matrix I am dealing with.
nn = 35000
dd = 35
XX = np.random.rand(nn,dd)
XX = XX.dot(XX.T) #it should be faster than np.dot(XX,XX.T)
yy = np.random.rand(nn,1)
XX = np.multiply(XX,yy.T)
I have to store this huge matrix XX, my guess: I split the matrix with
upp = np.triu(XX)
Do I actually save space in terms of stored data? What if later on I store
low = app.T
am I wasting memory and computational time?
回答1:
It should take up the same total amount of memory. To avoid the error you are probably looking at a few options:
- Process batch wise If you create your model over the CPLEX API, once you supplied the data it is handled by CPLEX I believe. So you could split the data and load it piece by piece and add it to the model consecutively.
- Allocate memory manually If you use Cython you can use the function malloc to allocate memory manually for your array, the size will very likely be no issue then.
Option 1 would be the preferred option in my opinion.
EDIT: I constructed a little example. It actually combines the two options. The array is not stored as a Python object, but as a C array and the values are computed piecewise. I am allocating the memory for the array using Cython and malloc. To run the code you have to install Cython.Then you can open a python interpreter at the directory you saved the file and write:
import pyximport;pyximport.install()
import nameofscript
An example for processing your array:
import numpy as np
from libc.stdlib cimport malloc # Allocate memory manually
from cython.parallel import prange # Parallel processing without GIL
dd = 35
# With cdef we can define C variables in Cython.
cdef double **XXN
cdef double y[35000]
cdef int i, j, nn
nn = 35000
# Allocate memory for the Matrix with 1.225 billion double elements
XXN = <double **>malloc(nn * sizeof(double *))
for i in range(nn):
XXN[i] = <double *>malloc(nn * sizeof(double))
XX = np.random.rand(nn,dd)
for i in range(nn):
for j in range(nn):
# Compute the values for the new matrix element by element
XXN[i][j] = XX[i].dot(XX[j].T)
# Multiply the new matrix with y column wise
for i in prange(nn, nogil=True, num_threads=4):
for j in range(nn):
XXN[i][j] = XXN[i][j] * y[i]
Save this file as nameofscript.pyx and run it as described above. I have briefly tested this script and it runs about half an hour on my machine. You can extend this script and use the result array XXN for your further computations. A little example for parallelization: I did not initialize y and did not assign any values. If you declare y as a C array, you can e. g. assign some values from python objects to fill it with values. Then, you can conduct the last multiplication without GIL, in a parallelized manner, as shown in the code sample.
Regarding computational efficiency: This is probably not the fastest way (which may be writing your code for the CPLEX C Interface entirely maybe), but it does not throw the memory error and does run in an acceptable time if you do not have to repeat this computation too often.
来源:https://stackoverflow.com/questions/41962488/decomposition-of-matrices-for-cplex-and-machine-learning-application