timestamp

问题 We have a ColdFusion 8 (Linux) application that uses an Oracle timestamp. We just converted to Oracle 11g from 10g and we're now using Oracle's thin client on the data sources. We're getting an error in the application where a timestamp column is selected. It seems as though an object of class oracle.sql.TIMESTAMP is being returned. I verified this by dumping the contents of the column. Sure enough, it gives me a break down of the object's methods and their return types. But, I can't seem to

问题 I'm trying to get the system time accurate to milliseconds in Windows cmd. I know that it's possible to get centisecond accuracy using: echo %time% I've found other questions that are asking the exact same thing but there is no answer that fully answers the question. Here is what I've found so far: This solution is only good for centisecond accuracy (same as what I described above): Print time in a batch file (milliseconds) This solution provides a timer solution but not a print current

问题 I'm trying to fetch last modified timestamp of a table in Hive. 回答1: Please use the below command: show TBLPROPERTIES table_name ('transient_lastDdlTime'); 回答2: Get the transient_lastDdlTime from your Hive table. SHOW CREATE TABLE table_name; Then copy paste the transient_lastDdlTime in below query to get the value as timestamp. SELECT CAST(from_unixtime(your_transient_lastDdlTime_value) AS timestamp); 回答3: You may get the timestamp by executing describe formatted table_name 回答4: you can

问题 I want to convert a date string to unix timestamp from a date string e.g. 14-02-2018 Can someone help? 回答1: Since JDK 8 you can do: val l = LocalDate.parse("14-02-2018", DateTimeFormatter.ofPattern("dd-MM-yyyy")) val unix = l.atStartOfDay(ZoneId.systemDefault()).toInstant().epochSecond Note that the example uses your system's default timezone. 回答2: use this to convert the date string to UNIX timestamp val date = SimpleDateFormat("dd-MM-yyyy").parse("14-02-2018") println(date.time) 来源： https:/

问题 I want to convert a date string to unix timestamp from a date string e.g. 14-02-2018 Can someone help? 回答1: Since JDK 8 you can do: val l = LocalDate.parse("14-02-2018", DateTimeFormatter.ofPattern("dd-MM-yyyy")) val unix = l.atStartOfDay(ZoneId.systemDefault()).toInstant().epochSecond Note that the example uses your system's default timezone. 回答2: use this to convert the date string to UNIX timestamp val date = SimpleDateFormat("dd-MM-yyyy").parse("14-02-2018") println(date.time) 来源： https:/

问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . Improve this question Where is the mistake in my code? package My; import java.text.SimpleDateFormat; import java.util.Date; public class Hello { public static void main(String[] args) { Date now = new Date(); SimpleDateFormat formatter = new SimpleDateFormat("MMM/dd/yyyy HH:mm:ss");

问题 How i can find the difference between two time stamps in minutes . for example:- timestamp1=2016-04-06 21:26:27 timestamp2=2016-04-07 09:06:02 difference = timestamp2-timestamp1 = 700 minutes (approx) 回答1: Using the datetime module: from datetime import datetime fmt = '%Y-%m-%d %H:%M:%S' tstamp1 = datetime.strptime('2016-04-06 21:26:27', fmt) tstamp2 = datetime.strptime('2016-04-07 09:06:02', fmt) if tstamp1 > tstamp2: td = tstamp1 - tstamp2 else: td = tstamp2 - tstamp1 td_mins = int(round(td

问题 How i can find the difference between two time stamps in minutes . for example:- timestamp1=2016-04-06 21:26:27 timestamp2=2016-04-07 09:06:02 difference = timestamp2-timestamp1 = 700 minutes (approx) 回答1: Using the datetime module: from datetime import datetime fmt = '%Y-%m-%d %H:%M:%S' tstamp1 = datetime.strptime('2016-04-06 21:26:27', fmt) tstamp2 = datetime.strptime('2016-04-07 09:06:02', fmt) if tstamp1 > tstamp2: td = tstamp1 - tstamp2 else: td = tstamp2 - tstamp1 td_mins = int(round(td

问题 I have datetime string "2019-11-02T20:18:00Z" . How can I convert it into timestamp in Hive HQL? 回答1: If you want preserve milliseconds then remove Z , replace T with space and convert to timestamp: select timestamp(regexp_replace("2019-11-02T20:18:00Z", '^(.+?)T(.+?)Z$','$1 $2')); Result: 2019-11-02 20:18:00 Also it works with milliseconds: select timestamp(regexp_replace("2019-11-02T20:18:00.123Z", '^(.+?)T(.+?)Z$','$1 $2')); Result: 2019-11-02 20:18:00.123 Using from_unixtime(unix

问题 I have a timestamp column and I get an errors when I try to enter some specific dates and times. For example 2013-03-31 02:13:11 and 2014-03-31 02:55:00 work, but 2013-03-31 02:55:00 says: SQL Error (1292): Incorrect datetime value What could be the problem? 回答1: This could be a daylight saving time issue, especially when you mention that the date causing problem is 2013-03-31 02:55:00 ... the date on which most European countries started observing DST for the year 2013. Central Europe Time