问题
I have a button in SwiftUI and I would like to be able to have a different action for "tap button" (normal click/tap) and "long press".
Is that possible in SwiftUI?
Here is the simple code for the button I have now (handles only the "normal" tap/touch case).
Button(action: {self.BLEinfo.startScan() }) {
Text("Scan")
} .disabled(self.BLEinfo.isScanning)
I already tried to add a "longPress gesture" but it still only "executes" the "normal/short" click. This was the code I tried:
Button(action: {self.BLEinfo.startScan() }) {
Text("Scan")
.fontWeight(.regular)
.font(.body)
.gesture(
LongPressGesture(minimumDuration: 2)
.onEnded { _ in
print("Pressed!")
}
)
}
Thanks!
Gerard
回答1:
I tried many things but finally I did something like this:
Button(action: {
}) {
VStack {
Image(self.imageName)
.resizable()
.onTapGesture {
self.action(false)
}
.onLongPressGesture(minimumDuration: 0.1) {
self.action(true)
}
}
}
It is still a button with effects but short and long press are different.
回答2:
This isn't tested, but you can try to add a LongPressGesture
to your button.
It'll presumably look something like this.
struct ContentView: View {
@GestureState var isLongPressed = false
var body: some View {
let longPress = LongPressGesture()
.updating($isLongPressed) { value, state, transaction in
state = value
}
return Button(/*...*/)
.gesture(longPress)
}
}
来源:https://stackoverflow.com/questions/58284994/swiftui-how-to-handle-both-tap-long-press-of-button