java program to calculate XIRR without using excel or any other library

余生长醉 提交于 2019-12-21 05:56:19

问题


My application have to calculate XIRR, but I cannot use excel, because it runs on Linux, can any one share the logic or java code to calculate XIRR without using excel.


回答1:


as stated in the post : xirr-calculation in c#

According to XIRR function openoffice documentation (formula is same as in excel) you need to solve for XIRR variable in the following f(xirr) equation: xirr equation

I just traduce the C# code in Java and it work well without any sup libraries. Even for date difference. But in production code, you will use something like apache common.

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

    public class XirrDate {

    public static final double tol = 0.001;    

    public static double dateDiff(Date d1, Date d2){
        long day = 24*60*60*1000;

        return (d1.getTime() - d2.getTime())/day;
    }

    public static double f_xirr(double p, Date dt, Date dt0, double x) {        
        return p * Math.pow((1.0 + x), (dateDiff(dt0,dt) / 365.0));
    }

    public static double df_xirr(double p, Date dt, Date dt0, double x) {        
        return (1.0 / 365.0) * dateDiff(dt0,dt) * p * Math.pow((x + 1.0), ((dateDiff(dt0,dt) / 365.0) - 1.0));
    }

    public static double total_f_xirr(double[] payments, Date[] days, double x) {
        double resf = 0.0;

        for (int i = 0; i < payments.length; i++) {
            resf = resf + f_xirr(payments[i], days[i], days[0], x);
        }

        return resf;
    }

    public static double total_df_xirr(double[] payments, Date[] days, double x) {
        double resf = 0.0;

        for (int i = 0; i < payments.length; i++) {
            resf = resf + df_xirr(payments[i], days[i], days[0], x);
        }

        return resf;
    }

    public static double Newtons_method(double guess, double[] payments, Date[] days) {
        double x0 = guess;
        double x1 = 0.0;
        double err = 1e+100;

        while (err > tol) {
            x1 = x0 - total_f_xirr(payments, days, x0) / total_df_xirr(payments, days, x0);
            err = Math.abs(x1 - x0);
            x0 = x1;
        }

        return x0;
    }

    private static SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
    public static Date strToDate(String str){
        try {
            return sdf.parse(str);
        } catch (ParseException ex) {
            return null;
        }
    }

    public static void main(String... args) {
        double[] payments = {-1151250,232912,233123,233336,233551,233768}; // payments
        Date[] days = {strToDate("11/11/2015"),strToDate("25/11/2015"),strToDate("25/12/2015"),strToDate("25/01/2016"),strToDate("25/02/2016"),strToDate("25/03/2016")}; // days of payment (as day of year)
        double xirr = Newtons_method(0.1, payments, days);

        System.out.println("XIRR value is " + xirr);    
    }}



回答2:


You can use org.decampo library for java implementation.

Note: The code which has been provided by @Doukya is showing wrong answer if you cross check with excel sheet calculated value.



来源:https://stackoverflow.com/questions/36789967/java-program-to-calculate-xirr-without-using-excel-or-any-other-library

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!