问题
MSDN states the following SortedSet(T).Add Method :
If Count is less than the capacity of the internal array, this method is an O(1) operation.
Could someone please explain "how so"? I mean when adding new value we need to find a correct place to add a value (comparing it with another values) and internal implementation looks like a "Red-Black tree" with O (log N) insertion complexity.
回答1:
The comment is simply wrong. Yes, it is a red-black tree, O(log(n)) for inserts. Taking a look with Reflector bears this out, the private AddIfNotPresent() method contains a while() loop to find the insertion point, using normal red-black node traversal.
This doc bug has already been submitted by you-know-who.
来源：https://stackoverflow.com/questions/2533007/add-to-sortedsett-and-its-complexity