Getopt optional arguments?

北战南征 提交于 2019-12-19 06:01:31

问题


I have a program where you enter an option -d and then whether or not you supply a non-optional argument after the option, do something.
Heres my code:

#include <stdio.h>
#include <getopt.h>
#include <stdlib.h>

#define OPT_LIST "d::" 

int main (int argc, char *argv[])
{
    int c;
    char string[] = "blah";

    while ((c = getopt (argc, argv, OPT_LIST)) != -1)
    {
        switch (c)
        {
            case 'd':
                    printf("%s\n", optarg);
                    break;

            case '?':
                fprintf(stderr, "invalid option\n");
                exit(EXIT_FAILURE);
        }   
    }
}

So if you enter a non-optional argument after the option, it prints the argument. But I want it to print out the char "string" if the user doesn't supply a non-optional argument (this is why I put the double colon in the OPT_LIST). But I'm not sure how to do this so any help would be greatly appreciated.

Heres what happens when I run the program:

user:desktop shaun$ ./arg -d hello
hello
user:desktop shaun$ ./arg -d 
./arg: option requires an argument -- d
invalid option

I'm running a Mac with OS X using C language.


回答1:


The "optional value of an option" feature is only a GNU libc extension, not required by POSIX, and is probably simply unimplemented by the libc shipped with Mac OS X.

The options argument is a string that specifies the option characters that are valid for this program. An option character in this string can be followed by a colon (‘:’) to indicate that it takes a required argument. If an option character is followed by two colons (‘::’), its argument is optional; this is a GNU extension.

https://www.gnu.org/software/libc/manual/html_node/Using-Getopt.html

In fact, POSIX.1-2008, section 12.2, "Utility Syntax Guidelines", explicitly forbids this feature:

Guideline 7: Option-arguments should not be optional.

http://pubs.opengroup.org/onlinepubs/9699919799/basedefs/V1_chap12.html#tag_12_02




回答2:


According to the getopt documentation, it will return : if an option with an argument does not have one. It also sets optopt with the matching argument.

Therefore, use:

int main (int argc, char *argv[])
{
    int c;
    while ((c = getopt (argc, argv, "d:f:")) != -1)
    {
        switch (c)
        {
            case 'd':
            case 'f':
                printf("option -%c with argument '%s'\n", c, optarg);
                break;
            case ':':
                switch (optopt)
                {
                case 'd':
                    printf("option -%c with default argument value\n", optopt);
                    break;
                default:
                    fprintf(stderr, "option -%c is missing a required argument\n", optopt);
                    return EXIT_FAILURE;
                }
                break;
            case '?':
                fprintf(stderr, "invalid option: -%c\n", optopt);
                return EXIT_FAILURE;
        }
    }
    return EXIT_SUCCESS;
}



回答3:


Maybe I'm misunderstanding the question. I'm reading it as though the user wants to over ride getopt's default error handling. If that is the case, shouldn't there be a : in the beginning of their OPT_LIST? I think the code above is good, however, I think it will still print

./arg: option requires an argument -- d

To surpress that, don't we need a : at the beginning of the OPT_LIST? For example, changing this:

while ((c = getopt (argc, argv, "d:f:")) != -1)

to this:

while ((c = getopt (argc, argv, ":d:f:")) != -1)

Correct me if I'm wrong.




回答4:


Try this solution. It works for me. Consider option 'z' as option with optional argument.

int c;
opterr = 0; //if (opterr != 0) (which it is by default), getopt() prints its own error messages for invalid options and for missing option arguments.
while ((c = getopt (argc, argv, "x:y:z:")) != -1)
    switch (c)
    {
        case 'x':
        case 'y':
        case 'z':
            printf("OK ... option -%c with argument '%s'\n", c, optarg);
            break;

        case '?':
            if (optopt == 'x' || optopt == 'y')
                fprintf (stderr, "ERR ... Option -%c requires an argument.\n", optopt);
            else if(optopt == 'z' && isprint(optopt))
            {
                printf("OK ... option '-z' without argument \n");
                break;
            }
            else if (isprint (optopt))
                fprintf (stderr, "ERR ... Unknown option `-%c'.\n", optopt);
            else
                fprintf (stderr, "ERR ... Unknown option character `\\x%x'.\n", optopt);
            return -1;
        default: ;
  }

Here are some examples:

./prog -x
    ERR ... Option -x requires an argument.

./prog -y
    ERR ... Option -x requires an argument.

./prog -z
    OK ... option '-z' without argument

./prog -x aaa
    OK ... option -x with argument 'aaa'

./prog -y bbb -x aaa
    OK ... option -y with argument 'bbb'
    OK ... option -x with argument 'aaa'

./prog -x aaa -y bbb -z
    OK ... option -x with argument 'aaa'
    OK ... option -y with argument 'bbb'
    OK ... option '-z' without argument

./prog -x aaa -y bbb -z ccc
    OK ... option -x with argument 'aaa'
    OK ... option -y with argument 'bbb'
    OK ... option -z with argument 'ccc'


来源:https://stackoverflow.com/questions/19604413/getopt-optional-arguments

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!