问题
I am currently trying to use Simulated Annealing package GenSA in order to minimize the function below :
efficientFunction <- function(v) {
t(v) %*% Cov_Mat %*% v
}
Where Cov_Mat is a covariance matrix obtained from 4 assets and v is a weight vector of dimension 4.
I'm trying to solve the Markowitz asset allocation approach this way and I would like to know how I could introduce mathematical constraint such as the sum of all coefficients have to equal 1 :
sum(v) = 1
Moreover since I intend to rely on the GenSA function, I would like to use something like this with the constraint :
v <- c(0.25, 0.25, 0.25, 0.25)
dimension <- 4
lower <- rep(0, dimension)
upper <- rep(1, dimension)
out <- GenSA(v, lower = lower, upper = upper, fn = efficientFunction)
I have found in this paper : http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.97.6091&rep=rep1&type=pdf how to handle such constraint within the Simulated Annealing Algorithm but I don't know how I could implement it in R.
I'd be very grateful for any advice. It is my first time using SO so don't hesitate to tell me if I have the wrong approach in the way I ask question.
回答1:
A possible approach would be to make use of so-called Lagrange multipliers (cf., http://en.wikipedia.org/wiki/Lagrange_multiplier). For example, set
efficientFunction <- function(v) {
lambda <- 100
t(v) %*% Cov_Mat %*% v + lambda * abs( sum(v) - 1 )
}
, so that in order to minimize the objective function efficientFunction
the resulting parameter also minimize the penalty term lambda * abs( sum(v) - 1 )
. The Lagrange multiplier lambda
is set to an arbitrary but sufficiently high level.
回答2:
So the function itself doesn't appear to have any constraints that you can set. However, you can reparameterize your function to force the constraint. How about
efficientFunction <- function(v) {
v <- v/sum(v)
t(v) %*% Cov_Mat %*% v
}
Here we normalize the values of v
so that they will sum to 1. Then, when we get the output parameters, we need to perform the same transformation
out <- GenSA(v, lower = lower, upper = upper, fn = efficientFunction)
out$par/sum(out$par)
来源:https://stackoverflow.com/questions/23808693/how-to-put-mathematical-constraints-with-gensa-function-in-r