Powershell Start Process, Wait with Timeout, Kill and Get Exit Code

问题

I want to repeatedly execute a program in a loop.

Sometimes, the program crashes, so I want to kill it so the next iteration can correctly start. I determine this via timeout.

I have the timeout working but cannot get the Exit Code of the program, which I also need to determine its result.

Before, I did not wait with timeout, but just used -wait in Start-Process, but this made the script hang if the started program crashed. With this setup I could correctly get the exit code though.

I am executing from ISE.

for ($i=0; $i -le $max_iterations; $i++)
{
    $proc = Start-Process -filePath $programtorun -ArgumentList $argumentlist -workingdirectory $programtorunpath -PassThru
    # wait up to x seconds for normal termination
    Wait-Process -Timeout 300 -Name $programname
    # if not exited, kill process
    if(!$proc.hasExited) {
        echo "kill the process"
        #$proc.Kill() <- not working if proc is crashed
        Start-Process -filePath "taskkill.exe" -Wait -ArgumentList '/F', '/IM', $fullprogramname
    }
    # this is where I want to use exit code but it comes in empty
    if ($proc.ExitCode -ne 0) {
       # update internal error counters based on result
    }
}

How can I

Start a process
Wait for it to orderly execute and finish
Kill it if it is crashed (e. g. hits timeout)
get exit code of process

回答1:

You can terminate the process more simply using $proc | kill or $proc.Kill(). Be aware, that you won't be able to retrieve a exit code in this case, you should rather just update the internal error counter:

for ($i=0; $i -le $max_iterations; $i++)
{
    $proc = Start-Process -filePath $programtorun -ArgumentList $argumentlist -workingdirectory $programtorunpath -PassThru

    # keep track of timeout event
    $timeouted = $null # reset any previously set timeout

    # wait up to x seconds for normal termination
    $proc | Wait-Process -Timeout 4 -ErrorAction SilentlyContinue -ErrorVariable timeouted

    if ($timeouted)
    {
        # terminate the process
        $proc | kill

        # update internal error counter
    }
    elseif ($proc.ExitCode -ne 0)
    {
        # update internal error counter
    }
}

来源：https://stackoverflow.com/questions/36933527/powershell-start-process-wait-with-timeout-kill-and-get-exit-code

标签

powershell

wait

exit-code

start-process