问题

Motivation: reason why I'm considering it is that my genius project manager thinks that boost is another dependency and that it is horrible because "you depend on it"(I tried explaining the quality of boost, then gave up after some time :( ). Smaller reason why I would like to do it is that I would like to learn c++11 features, because people will start writing code in it. So:

Is there a 1:1 mapping between #include<thread> #include<mutex>and boost equivalents?
Would you consider a good idea to replace boost stuff with c++11
stuff. My usage is primitive, but are there examples when std doesnt offer what boost does? Or (blasphemy) vice versa?

P.S. I use GCC so headers are there.

回答1:

There are several differences between Boost.Thread and the C++11 standard thread library:

Boost supports thread cancellation, C++11 threads do not
C++11 supports std::async, but Boost does not
Boost has a boost::shared_mutex for multiple-reader/single-writer locking. The analogous std::shared_timed_mutex is available only since C++14 (N3891), while std::shared_mutex is available only since C++17 (N4508).
C++11 timeouts are different to Boost timeouts (though this should soon change now Boost.Chrono has been accepted).
Some of the names are different (e.g. boost::unique_future vs std::future)
The argument-passing semantics of std::thread are different to boost::thread --- Boost uses boost::bind, which requires copyable arguments. std::thread allows move-only types such as std::unique_ptr to be passed as arguments. Due to the use of boost::bind, the semantics of placeholders such as _1 in nested bind expressions can be different too.
If you don't explicitly call join() or detach() then the boost::thread destructor and assignment operator will call detach() on the thread object being destroyed/assigned to. With a C++11 std::thread object, this will result in a call to std::terminate() and abort the application.

To clarify the point about move-only parameters, the following is valid C++11, and transfers the ownership of the int from the temporary std::unique_ptr to the parameter of f1 when the new thread is started. However, if you use boost::thread then it won't work, as it uses boost::bind internally, and std::unique_ptr cannot be copied. There is also a bug in the C++11 thread library provided with GCC that prevents this working, as it uses std::bind in the implementation there too.

void f1(std::unique_ptr<int>);
std::thread t1(f1,std::unique_ptr<int>(new int(42)));

If you are using Boost then you can probably switch to C++11 threads relatively painlessly if your compiler supports it (e.g. recent versions of GCC on linux have a mostly-complete implementation of the C++11 thread library available in -std=c++0x mode).

If your compiler doesn't support C++11 threads then you may be able to get a third-party implementation such as Just::Thread, but this is still a dependency.

回答2:

std::thread is largely modelled after boost::thread, with a few differences:

boost's non-copyable, one-handle-maps-to-one-os-thread, semantics are retained. But this thread is movable to allow returning thread from factory functions and placing into containers.

This proposal adds cancellation to the boost::thread, which is a significant complication. This change has a large impact not only on thread but the rest of the C++ threading library as well. It is believed this large change is justifiable because of the benefit.
The thread destructor must now call cancel prior to detaching to avoid accidently leaking child threads when parent threads are canceled.

An explicit detach member is now required to enable detaching without canceling.

The concepts of thread handle and thread identity have been separated into two classes (they are the same class in boost::thread). This is to support easier manipulation and storage of thread identity.

The ability to create a thread id which is guaranteed to compare equal to no other joinable thread has been added (boost::thread does not have this). This is handy for code which wants to know if it is being executed by the same thread as a previous call (recursive mutexes are a concrete example).

There exists a "back door" to get the native thread handle so that clients can manipulate threads using the underlying OS if desired.

This is from 2007, so some points are no longer valid: boost::thread has a native_handle function now, and, as commenters point out, std::thread doesn't have cancellation anymore.

I could not find any significant differences between boost::mutex and std::mutex.

回答3:

There is one reason not to migrate to std::thread.

If you are using static linking, std::thread becomes unusable due to these gcc bugs/features:

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=52590
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=57740

Namely, if you call std::thread::detach or std::thread::join it will lead to either exception or crash, while boost::thread works ok in these cases.

回答4:

Enterprise Case

If you are writing software for the enterprise that needs to run on a moderate to large variety of operating systems and consequently build with a variety of compilers and compiler versions (especially relatively old ones) on those operating systems, my suggestion is to stay away from C++11 altogether for now. That means that you cannot use std::thread, and I would recommend using boost::thread.

Basic / Tech Startup Case

If you are writing for one or two operating systems, you know for sure that you will only ever need to build with a modern compiler that mostly supports C++11 (e.g. VS2015, GCC 5.3, Xcode 7), and you are not already dependent on the boost library, then std::thread could be a good option.

My Experience

I am personally partial to hardened, heavily used, highly compatible, highly consistent libraries such as boost versus a very modern alternative. This is especially true for complicated programming subjects such as threading. Also, I have long experienced great success with boost::thread (and boost in general) across a vast array of environments, compilers, threading models, etc. When its my choice, I choose boost.

回答5:

With Visual Studio 2013 the std::mutex seems to behave differently than the boost::mutex, which caused me some problems (see this question).

回答6:

With regards to std::shared_mutex added in C++17

The other answers here provide a very good overview of the differences in general. However, there are several issues with std::shared_mutex that boost solves.

Upgradable mutices. These are absent from std::thread. They allow a reader to be upgraded to a writer without allowing any other writers to get in before you. These allow you to do things like pre-process a large computation (for example, reindexing a data structure) when in read mode, then upgrade to write to apply the reindex while only holding the write lock for a short time.
Fairness. If you have constant read activity with a std::shared_mutex, your writers will be softlocked indefinitely. This is because if another reader comes along, they will always be given priority. With boost:shared_mutex, all threads will eventually be given priority.⁽¹⁾ Neither readers nor writers will be starved.

The tl;dr of this is that if you have a very high-throughput system with no downtime and very high contention, std::shared_mutex will never work for you without manually building a priority system on top of it. boost::shared_mutex will work out of the box, although you might need to tinker with it in certain cases. I'd argue that std::shared_mutex's behavior is a latent bug waiting to happen in most code that uses it.

⁽¹⁾_{The actual algorithm it uses is based on the OS thread scheduler. In my experience, when reads are saturated, there are longer pauses (when obtaining a write lock) on Windows than on OSX/Linux.}

回答7:

I tried to use shared_ptr from std instead of boost and I actually found a bug in gcc implementation of this class. My application was crashing because of destructor called twice (this class should be thread-safe and shouldn't generate such problems). After moving to boost::shared_ptr all problems disappeared. Current implementations of C++11 are still not mature.

Boost has also more features. For example header in std version doesn't provide serializer to a stream (i.e. cout << duration). Boost has many libraries that use its own , etc. equivalents, but do not cooperate with std versions.

To sum up - if you already have an application written using boost, it is safer to keep your code as it is instead of putting some effort in moving to C++11 standard.

来源：https://stackoverflow.com/questions/7241993/is-it-smart-to-replace-boostthread-and-boostmutex-with-c11-equivalents

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