问题
I got an error:
Parse error: syntax error, unexpected end of file in the line
With this code:
<html>
<?php
function login()
{
// Login function code
}
if (login())
{?>
<h2>Welcome Administrator</h2>
<a href=\"upload.php\">Upload Files</a>
<br />
<a href=\"points.php\">Edit Points Tally</a>
<?php}
else
{
echo "Incorrect login details. Please login";
}
?>
Some more HTML code
</html>
What's the problem?
回答1:
You should avoid this (at the end of your code):
{?>
and this:
<?php}
You shouldn't put brackets directly close to the open/close php tag, but it separate with a space:
{ ?>
<?php {
also avoid <? and use <?php
回答2:
I had the same error, but I had it fixed by modifying the php.ini file.
Find your php.ini file see Dude, where's my php.ini?
then open it with your favorite editor.
Look for a short_open_tag property, and apply the following change:
; short_open_tag = Off ; previous value
short_open_tag = On ; new value
回答3:
I had the same error, but I had it fixed by modifying the php.ini and / or editing the PHP file!
There are two different methods to get around the parse error syntax.
Method 1 (Your PHP file)
Avoid in your PHP file this:
<? } ?>
Make sure you put it like this
<?php ?>
Your code contains
<? ?>NOTE: The missing
phpafter<?!
Method 2 (php.ini file)
There is also a simple way to solve your problem.
Search for the short_open_tag property value (Use in your text editor with Ctrl + F!), and apply the following change:
; short_open_tag = Off
to
short_open_tag = On
According to the description of core php.ini directives, short_open_tag allows you to use the short open tag (<?) although this might cause issues when used with xml (<?xml will not work when this is enabled)!
NOTE: Reload your Server (like for example: Apache) and reload your PHP webpage in your browser.
回答4:
Just go to php.ini then find short_open_tag= Off set to short_open_tag= On
回答5:
Look for any loops or statements are left unclosed.
I had ran into this trouble when I left a php foreach: tag unclosed.
<?php foreach($many as $one): ?>
Closing it using the following solved the syntax error: unexpected end of file
<?php endforeach; ?>
Hope it helps someone
回答6:
Check that you closed your class.
For example, if you have controller class with methods, and by accident you delete the final bracket, which close whole class, you will get this error.
class someControler{
private $varr;
public $varu;
..
public function method {
..
}
..
}// if you forget to close the controller, you will get the error
回答7:
also, look for a comment // that breaks the closing curly brace
if (1==1) { //echo "it is true"; }
the closing curly brace will not properly close the conditional section and php won't properly process the remainder of code.
回答8:
Avoid this as well <? } ?> make sure you put <?php } ?>
回答9:
I saw some errors, which I've fixed below.
This is what I got as being erroneous:
if (login())
{?>
<h2>Welcome Administrator</h2>
<a href=\"upload.php\">Upload Files</a>
<br />
<a href=\"points.php\">Edit Points Tally</a>
<?php}
else
{
echo "Incorrect login details. Please login";
}
This is how I would have done it:
<html>
some code
<?php
function login()
{
if (empty ($_POST['username']))
{
return false;
}
if (empty ($_POST['password']))
{
return false;
}
$username = trim ($_POST['username']);
$password = trim ($_POST['password']);
$scrambled = md5 ($password . 'foo');
$link = mysqli_connect('localhost', 'root', 'password');
if (!$link)
{
$error = "Unable to connect to the database server";
include 'error.html.php';
exit ();
}
if (!mysqli_set_charset ($link, 'utf8'))
{
$error = "Unable to set database connection encoding";
include 'error.html.php';
exit ();
}
if (!mysqli_select_db ($link, 'foo'))
{
$error = "Unable to locate the foo database";
include 'error.html.php';
exit ();
}
$sql = "SELECT COUNT(*) FROM admin WHERE username = '$username' AND password = '$scrambled'";
$result = mysqli_query ($link, $sql);
if (!$result)
{
return false;
exit ();
}
$row = mysqli_fetch_array ($result);
if ($row[0] > 0)
{
return true;
}
else
{
return false;
}
}
if (login())
{
echo '<h2>Welcome Administrator</h2>
<a href=\"upload.php\">Upload Files</a>
<br />
<a href=\"points.php\">Edit Points Tally</a>';
}
else
{
echo "Incorrect login details. Please login";
}
?>
some more html code
</html>
回答10:
In my case the culprit was the lone opening <?php tag in the last line of the file. Apparently it works on some configurations with no problems but causes problems on others.
回答11:
For me, the most frequent cause is an omitted } character, so that a function or if statement block is not terminated. I fix this by inserting a } character after my recent edits and moving it around from there. I use an editor that can locate opening brackets corresponding to a closing bracket, so that feature helps, too (it locates the function that was not terminated correctly).
We can hope that someday language interpreters and compilers will do some work to generate better error messages, since it is so easy to omit a closing bracket.
If this helps anyone, please vote the answer up.
回答12:
You can't divide IF/ELSE instructions into two separate blocks. If you need HTML code to be printed, use echo.
<html>
<?php
function login()
{
// Login function code
}
if (login())
{
echo "<h2>Welcome Administrator</h2>
<a href=\"upload.php\">Upload Files</a>
<br />
<a href=\"points.php\">Edit Points Tally</a>";
}
else
{
echo "Incorrect login details. Please login";
}
?>
Some more HTML code
</html>
回答13:
Also, another case where it is hard to spot is when you have a file with just a function, I know it is not a common use case but it is annoying and had to spot the error.
<?php
function () {
}
The file above returns the erro Parse error: syntax error, unexpected end of file in while the below does not.
<?php
function () {
};
回答14:
If your using parse_ini_file($file) or a routine is rading an .ini file, check if you data is quoted in the ini file. Unquoted data will cause this error. Ex; data1=test will cause the error, data1="test" will not.
来源：https://stackoverflow.com/questions/11482527/parse-error-syntax-error-unexpected-end-of-file-in-my-php-code