问题
I tried the following code snippet with MSVC 10, where it works fine.
enum
{
FOO = (sizeof(void*) == 8 ? 10 : 20)
};
int main()
{
return FOO;
}
What I would like to know is: Does the C++ Standard (preferably C++98) allow me to use the conditional-operator in a constant expression when all operands are constant expressions, or is this a Microsoft quirk/extension?
回答1:
This is perfectly valid and sensible standard C++.
The ternary conditional operator forms an expression, and the expression is a constant expression if its operands are.
The standard reference is C++11 5.19/2:
A conditional-expression is a core constant expression [...]
Note that by 5.16, ternary conditional expressions are one type of conditional-expressions. Other types are things like 2 == 3
.
来源:https://stackoverflow.com/questions/16549631/conditional-operator-in-constant-expression