问题
Suppose I have a set of hypotesys H = {h1, h2} mutual exclusive. For them P(h1) = 0.2 and p(h3) = 0.3 (prior distribution). Suppose we know also that
P(Y=0 | h1) = 0.2 P(Y=0 | h2) = 0.4
where Y is an attribute (target) that can have two values {1,0}. Suppose finally that you observe the event Y = 0.
Which one is the MAP (Maximum a posteriori) hipotesys?
- MAP is h1
- MAP is h2
- there's no enough element to find MAP
- MAP h1 = MAP h2
- nobody of the possible answer above
回答1:
Such question should be asked (and now probably migrated) on the math.stackexchange.com or stats.stackexchange.com .
Your question is basic application of the Bayes Theorem
P(Y=0|h1)P(h1) 0.2*0.2 0.04
P(h1|Y=0) = ------------- = ------- = ------
P(Y=0) P(Y=0) P(Y=0)
P(Y=0|h2)P(h2) 0.3*0.4 0.12
P(h2|Y=0) = -------------- = ------- = ------
P(Y=0) P(Y=0) P(Y=0)
So the h2
is the more probable hypothesis, as P(Y=0)>0
来源:https://stackoverflow.com/questions/18673294/bayes-learning-map-hypotesis