In python, is a function return a shallow or deep copy?

问题

In python, if I have

x = y

any modification to x will also modify y, and I can do

x = deepcopy(y)

if I want to avoid modifying y while working on x

Say, instead, that I have:

myFunc():
    return y

def main():
    x = myFunc()

Is it still the case that modifying x will modify y, or since it is a return from another function it will be like a deepcopy?

回答1:

It will be a shallow copy, as nothing has been explicitly copied.

def foo(list):
    list[1] = 5
    return list

For example:

>>> listOne = [1, 2]
>>> listTwo = [3, 4]
>>> listTwo = listOne
>>> foo(listTwo)
[1, 5]
>>> listOne
[1, 5]

回答2:

In python everything is a reference. Nothing gets copied unless you explicitly copy it.

In your example, x and y reference the same object.

来源：https://stackoverflow.com/questions/42032384/in-python-is-a-function-return-a-shallow-or-deep-copy