问题
I have a frame data "testData" as follows:
id content
1 I came from China
2 I came from America
3 I came from Canada
4 I came from Japan
5 I came from Mars
And I also have another frame data "addr" as follows:
id addr
1 America
2 Canada
3 China
4 Japan
Then how can I use grepl
, sapply
or any other useful function in R to generate data into as follows:
id content addr
1 I came from China China
2 I came from America America
3 I came from Canada Canada
4 I came from Japan Japan
5 I came from Mars Mars
回答1:
This does the trick:
vec = addr$addr
testData$addr = apply(testData, 1, function(u){
bool = sapply(vec, function(x) grepl(x, u[['content']]))
if(any(bool)) vec[bool] else NA
})
回答2:
Looks like you just want to replicate the column and remove "I came from "
testData$addr <- gsub("I came from ", testData$content)
回答3:
Here is a crude solution using some tidyverse
functions:
df1 <- read.table(text = "id content
1 'it is China'
2 'She is in America now'
3 'Canada is over there'
4 'He comes from Japan'
5 'I came from Mars'", header = TRUE, stringsAsFactors = FALSE)
df2 = read.table(text = "id addr
1 America
2 Canada
3 China
4 Japan
5 Mars", header = TRUE, stringsAsFactors = FALSE)
library(tidyverse)
crossing(df1, df2 %>% select(addr)) %>% # this creates a data frame of every possible content and add combination
rowwise() %>%
filter(str_detect(content, add)) # str_detect is the same as grepl, though the arguments are reversed. This filters to only observations where addr is in content.
# A tibble: 5 x 3
id content addr
<int> <chr> <chr>
1 1 it is China China
2 2 She is in America now America
3 3 Canada is over there Canada
4 4 He comes from Japan Japan
5 5 I came from Mars Mars
来源:https://stackoverflow.com/questions/28230360/using-grepl-in-r-to-match-string