Pattern Output, stuck

问题

Pretty new to all this, but here i go...

I need to make 2 patterns using a table (without borders) and for-loops:

1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6

I did work this one out with (probably not the easiest way tho, but it works):

<table>
        <b>Patroon I</b>
        <?php
            $pattern = array();
            for($pyramid = 1; $pyramid <=6; $pyramid++){
                $pattern[$pyramid] = $pyramid;
                echo "<tr>
                        <td class='td1'>" . $pattern[1] . "</td>";
                        if(array_key_exists(2, $pattern)){
                            echo "<td class='td1'>" . $pattern[2] . "</td>";
                        }
                        if(array_key_exists(3, $pattern)){
                            echo "<td class='td1'>" . $pattern[3] . "</td>";
                        }
                        if(array_key_exists(4, $pattern)){
                            echo "<td class='td1'>" . $pattern[4] . "</td>";
                        }
                        if(array_key_exists(5, $pattern)){
                            echo "<td class='td1'>" . $pattern[5] . "</td>";
                        }
                        if(array_key_exists(6, $pattern)){
                            echo "<td class='td1'>" . $pattern[6] . "</td>";
                        }
                echo "</tr>";
            }
        ?>
</table>

and the other pattern

1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1

Which I can't seem to figure out.
I tried to turn the previous code around, tried rsort($pattern), tried a lot of IF-statements, and now im stuck :S

Anyone has a hint for me?

Thanks!

回答1:

You don't need any array or fancy function, just two nested for loops.

<table>
        <?php
            // 1
            // 1 2
            // 1 2 3
            // ...
            $rows = 6;
            for ($row = 1; $row <= $rows; $row++) {
                echo "<tr>";
                for ($col = 1; $col <= $row; $col++) {
                    echo "<td class='td1'>" . $col . "</td>";
                }
                echo "</tr>";
            }
        ?>
</table>

<br />

<table>
        <?php
            // 1 2 3 4 5 6
            // 1 2 3 4 5
            // 1 2 3 4
            // ...
            $rows = 6;
            for ($row = $rows; $row > 0; $row--) {
                echo "<tr>";
                for ($col = 1; $col <= $row; $col++) {
                    echo "<td class='td1'>" . $col . "</td>";
                }
                echo "</tr>";
            }
        ?>
</table>

Add the following code before the closing row tag for balanced table rows.

if ($span = $rows - $row)
    echo  "<td colspan='$span'></td>";

回答2:

Try to 2 loops for getting output. Dont use array

  <b>Patroon I</b>
  <br>
  <?php

      for($pyramid = 1; $pyramid <=6; $pyramid++){
          for($i=1;$i<=$pyramid;$i++)
          {
            echo $i." ";
          }
          echo "<br>";
      }
  ?>
  <b>Patroon II</b>
  <br>
  <?php

      for($pyramid = 6; $pyramid >=1; $pyramid--){
          for($i=1;$i<=$pyramid;$i++)
          {
            echo $i." ";
          }
          echo "<br>";
      }
  ?>

回答3:

<?php
$pattern=array(1,2,3,4,5,6);
//var_dump($pattern);
 for($pyramid1 = 6; $pyramid1 >=0; $pyramid1--){
     echo "<tr>
            <td class='td1'>";
          for($i = 0; $i <=$pyramid1; $i++){
    echo  $pattern[$i] ;
          }
          echo "</td>";
     echo "</tr>";
       } 
      ?>
       </table>

来源：https://stackoverflow.com/questions/46197415/pattern-output-stuck