问题
I want different colors for alternate table rows even when i delete a row in middle.
HTML
<table border="1">
<tr><td>Row 1</td><td><a class="sam" href="#">Delete</a></td></tr>
<tr><td>Row 2</td><td><a class="sams" href="#">Delete</a></td></tr>
<tr><td>Row 3</td><td><a class="sam" href="#">Delete</a></td></tr>
<tr><td>Row 4</td><td><a class="sams" href="#">Delete</a></td></tr>
<tr><td>Row 5</td><td><a class="sam" href="#">Delete</a></td></tr>
</table>
Jquery
$(function(){
update_rows();
$("a").click(function(){$(this).parent().parent().remove();update_rows();});
});
function update_rows()
{
$("tr:even").css("background-color", "#aaa");
$("tr:odd").css("background-color", "#eee");
}
css
.sam
{
background-color:#FF00FF;
}
.sams
{
background-color:#0000FF;
}
the above code change the row color but not the cell which has link. Please help me to solve the problem
Demo
回答1:
You need to change the class as well
function update_rows() {
$("tr:even").css("background-color", "#aaa").find('a').removeClass('sam').addClass('sams');
$("tr:odd").css("background-color", "#eee").find('a').removeClass('sams').addClass('sam');
}
Demo: Fiddle
Use :nth-child if want to support only modern browsers - Demo: Fiddle
tr:nth-child(odd) a {
background-color:#FF00FF;
}
tr:nth-child(even) a {
background-color:#0000FF;
}
tr:nth-child(odd) {
background-color:#aaa;
}
tr:nth-child(even) {
background-color:#eee;
}
then
$(function () {
$("a").click(function () {
$(this).closest('tr').remove();
});
});
Also note: use $(this).closest('tr').remove()
instead of $(this).parent().parent().remove()
回答2:
Try:
<style>
tr:nth-of-type(even) {
background-color:#e3e3e3;
}
td:nth-of-type(odd) {
color:#d04242;
}
</style>
回答3:
Use CSS3 for the styling:
<table id="whatever">
<tr><td>Row 1</td><td><a href="#">Delete</a></td></tr>
<tr><td>Row 2</td><td><a href="#">Delete</a></td></tr>
<tr><td>Row 3</td><td><a href="#">Delete</a></td></tr>
<tr><td>Row 4</td><td><a href="#">Delete</a></td></tr>
<tr><td>Row 5</td><td><a href="#">Delete</a></td></tr>
</table>
<style>
#whatever tr {
background-color: #AAA;
}
#whatever tr a {
background-color:#F0F;
}
#whatever tr:nth-child(odd) {
background-color: #EEE;
}
#whatever tr:nth-child(odd) a {
background-color:#00F;
}
</style>
<script>
$("#whatever a").click(function(){
$(this).closest("tr").remove();
});
</script>
Now no manual updating, neither for the link classes nor the row backgrounds is needed. See updated demo.
回答4:
works perfectly with your tr. the link color doesent change because youre not targeting it with jQuery
回答5:
I have updated the fiddle You need the update the class sam and sams
$("tr:even td a").removeClass("sam").removeClass("sams").addClass("sam");
$("tr:odd td a").removeClass("sam").removeClass("sams").addClass("sams");
Check on fiddle
来源:https://stackoverflow.com/questions/20995526/alternate-table-row-color-even-if-row-is-removed