问题
How can I determine if a project is build in Debug (or Release) mode within an MSBuild .targets file and use this information as a condition for another property?
Something like:
<OutDir Condition="IsDebug">bin\Debug\$(SomeOtherProperty)\</OutDir>
<OutDir Condition="!IsDebug">bin\Release\$(SomeOtherProperty)\</OutDir>
Is there such thing as Debug/Release mode, or are they just conventional names for different sets of configuration properties' values?
回答1:
Debug/Release or whatever are just conventional values for the Configuration property.
So, as long the project that includes/calls your .targets file adheres to the convention; you can check for debug mode as follows:
<OutDir>bin\Release\$(SomeOtherProperty)\</OutDir>
<OutDir Condition=" '$(Configuration)' == 'Debug' ">bin\Debug\$(SomeOtherProperty)\</OutDir>
or you could just use that variable directly:
<OutDir>bin\$(Configuration)\$(SomeOtherProperty)\</OutDir>
来源：https://stackoverflow.com/questions/20800726/msbuild-condition-isdebug