问题
I had a bean object with me in the colmodel of jqgrid. the object hold two attributes name and id. I used a showLink formatter to form the hyperlink in one of the column. Now i have names the colum with object.name and on click i want to send the id in URL. Any inputs on how to work on this. Any inputs could help me
code :
colModel :[
{name:'xxx', label:'xxx', width:200,align:'left'},
{name:'yyy', label:'yyy', width:110,align:'left'},
{
name:'zzz',
label:'zzz',
width:100,
sorttype:'int',
formatter:'currency',
formatoptions:{decimalSeparator:".", thousandsSeparator: ",", decimalPlaces: 0, prefix: "$ "},
align:'center'
},
{name:'aaa', label:'aaa', width:80,align:'left'},
{name:'bbb', label:'bbb', width:100,align:'left'},
{
name:'strategies.name',
label:'strategies',
width:160,
align:'left',
formatter:'showlink',
formatoptions:{baseLinkUrl:'MyLink.html',addParam: '',showAction:'',idName:'id'}
}]
jQuery("#gridtableid").jqGrid('filterToolbar',{defaultSearch : "cn",stringResult: true,searchOnEnter : false});
Thanks in advance....
回答1:
In JQgrid, you can call a javascript function and do any required formatting . You have the entire row data to play with it.
What needs to be done is call a function showlink in your case and remove formatoptions from that row. HAve a separate js function showlink as below and return the prepared link back to the grid.
function showLink(cellvalue, options, rowObject) {
var link = "<a href ='<a href=\"http://www.w3schools.com&id='"+rowObject.columnid+"\">'+ rowObject.columnName + "</a>";
}
来源:https://stackoverflow.com/questions/9379639/passing-different-column-id-in-jqgrid-showlink-formatter