问题
I have an image with the following pattern:
I want to convert the straight lines in the image into a )|( shape. I have implemented C-type and S-type curves using canvas and its properties, but I am unable to do )|(-curve.
How can I do this?
回答1:
You could modify my previous answer slightly and have the halve sin range applied to the width (or height) as an offset, then take that offset x 2 and subtract from the total height of the new line.
What happens is that the sin() function will take an input and produce a new value between [0.0, 1.0]. Normally you would combine sin+cos to produce a circle, but we only need the value from one axis, and since we only need more of a ellipse shape we scale with a smaller value than radius (image size would represents diameter on the axis you're after).
So with the couple of modifications on the code I made in the other answer:
var ctx = c.getContext("2d"); // just some inits for demo
var img = new Image;
img.onload = slice;
img.src = "//i.stack.imgur.com/UvqUP.gif";
function slice() {
var w = c.width = this.width;
var h = c.height = this.height;
var step = Math.PI / w; // half circle / width of canvas
var scale = 75; // max displacement on y
for(var x = 0, offset; x < w; x++) {
offset = Math.sin(step*x)*scale;
ctx.drawImage(this,
x, 0, 1, h, // source line from image
x, offset, 1, h - offset*2); // displaced line
}
}
<canvas id=c></canvas>
(for vertical effect just reference where the changes are in the previous answer and apply offset instead of the formula).
回答2:
Use the distance from the horizontal center to apply a sin wave to the image scale. You only want part of the sin wave (PI/2 to PI) or (cos 0 to PI/2)
var img = new Image;
img.src = "//i.stack.imgur.com/UvqUP.gif";
var ctx = can.getContext("2d");
img.onload = function () {
var w,h,ch,cw,amount,x,scale;
w = can.width = this.width;
h = can.height = this.height;
cw = w / 2;
ch = h / 2;
amount = 50; // amount to bend in pixels
amount *= 1 / ch; // convert to unit scale
for(var x = 0; x < w; x++) {
scale = 1.0 - (Math.cos(((cw - x) / cw) * Math.PI * 0.5)) * amount;
ctx.drawImage(this, x, 0, 1, h, x, ch - ch * scale , 1, h * scale);
}
}
<canvas id="can"></canvas>
来源:https://stackoverflow.com/questions/42733727/how-to-convert-image-pixel-into-curve-shape-in-canvas