问题
I have been trying to generate an .exe for the following script using py2exe :
import snowflake.connector
import os
import sys
# Setting your account information
ACCOUNT = '########'
USER = '#######'
PASSWORD = '#######'
ROLES=[]
DATABASE=[]
ROLES.append(sys.argv[1])
DATABASE.append(sys.argv[2])
print(ROLES)
print(DATABASE)
cnx = snowflake.connector.connect(
user=USER,
password=PASSWORD,
account=ACCOUNT,
)
cur = cnx.cursor()
list_of_grants=[]
for rl in ROLES:
print("Role: "+rl )
db_res=cur.execute("SHOW DATABASES").fetchall()
for db in DATABASE:
print("Database: "+ db)
use_db_query = "USE DATABASE " + db
print(use_db_query)
cur.execute(use_db_query)
schema_res= cur.execute("SHOW SCHEMAS").fetchall()
for sch in schema_res:
print("schema: "+ sch[1])
list_of_grants.append("GRANT ALL ON SCHEMA "+db+"."+sch[1]+" to role "+rl+" with grant option")
use_db_query = "USE SCHEMA " + sch[1]
cur.execute(use_db_query)
tables_res=cur.execute("SHOW TABLES IN "+sch[1]).fetchall()
for tbl in tables_res:
print("table: "+ tbl[1])
list_of_grants.append("GRANT ALL ON TABLE "+db+"."+sch[1]+"."+tbl[1]+" to role "+rl+" with grant option")
for grant in list_of_grants:
cur.execute(grant)
The code is pretty straightforward and works like a charm.
I wish to turn it into a .exe with using py2exe but at that moment I got the following error :
running py2exe
Error: Namespace packages not yet supported: Skipping package 'snowflake'
Traceback (most recent call last):
File "setup.py", line 13, in <module>
'packages': ['snowflake']
File "C:\Anaconda3\lib\distutils\core.py", line 148, in setup
dist.run_commands()
File "C:\Anaconda3\lib\distutils\dist.py", line 955, in run_commands
self.run_command(cmd)
File "C:\Anaconda3\lib\distutils\dist.py", line 974, in run_command
cmd_obj.run()
File "C:\Anaconda3\lib\site-packages\py2exe\distutils_buildexe.py", line 188, in run
self._run()
File "C:\Anaconda3\lib\site-packages\py2exe\distutils_buildexe.py", line 267, in _run
builder.analyze()
File "C:\Anaconda3\lib\site-packages\py2exe\runtime.py", line 168, in analyze
mf.import_package(modname)
File "C:\Anaconda3\lib\site-packages\py2exe\mf3.py", line 92, in import_package
self.import_hook(name)
File "C:\Anaconda3\lib\site-packages\py2exe\mf3.py", line 120, in import_hook
module = self._gcd_import(name)
File "C:\Anaconda3\lib\site-packages\py2exe\mf3.py", line 274, in _gcd_import
return self._find_and_load(name)
File "C:\Anaconda3\lib\site-packages\py2exe\mf3.py", line 337, in _find_and_load
raise ImportError(name)
ImportError: snowflake
Snowflake is a package that allow me to connect to my DB (a snowflake database, rather new)
My os is : Windows 10, Python version 3.5.1
My setup.py for py2exe :
from distutils.core import setup
import snowflake.connector
import py2exe, sys, os
sys.argv.append('py2exe')
setup(
console=['grants.py'],
options = {
'py2exe': {
'packages': ['snowflake']
}
}
)
I looked around and couldn't find any answer to this problem. If anyone have an idea.
Thanks in advance for your help.
回答1:
snowflake
is a namespace package and not an actual package. Hence, the importer doesn't reach snowflake.connector
. To resolve the package issue, you will need to add __init__.py
in the Snowflake directory. Despite this fix, it appears there are other issues in creating an executable with py2exe. I suggest using 'pyinstaller' which works fine in creating an executable.
回答2:
import snowflake.connector
def createSnowflakeConn():
print("Creating snowflake connection")
__conn = snowflake.connector.connect(
user="your login name",
password="user password",
account="account id",
role="login role",
warehouse="warehouse to query"
)
return __conn
class WarehouseCursor(object):
def __init__(self):
self.__cursor = None
self.__conn = None
self.__conn = createSnowflakeConn()
Above code will help you with connecting Snowflake. Use of snowflake.connector package would solve your problem
来源:https://stackoverflow.com/questions/36191922/py2exe-error-namespace-packages-not-yet-supported-skipping-package-snowflake