问题
I have an application which reads xls sheet using apache poi. When the cell has numeric value, i read it by row.getCell(i).getNumericValue(). But it returns floating point digit. like if the cell value is 1, it returns 1.0. Can i convert it to int ? Any helpwould be appreciated. I tried Integer.parseInt(value)- but it throws NumberFormat exception.Any help is appreciated.Here is the pseudo code:
FileInputStream file = new FileInputStream(new File("C:\\test.xls"));
HSSFWorkbook workbook = new HSSFWorkbook(file);
HSSFSheet sheet = workbook.getSheetAt(0);
Iterator<Row> rowIterator = sheet.iterator();
while(rowIterator.hasNext()) {
Row row = rowIterator.next();
Iterator<Cell> cellIterator = row.cellIterator();
while(cellIterator.hasNext()) {
Cell cell = cellIterator.next();
switch(cell.getCellType()) {
case Cell.CELL_TYPE_NUMERIC:
String value= String.valueOf(cell.getNumericCellValue());
int intVal = Integer.parseInt(value)-->>throws Exception
回答1:
You can read int value as string apache poi using simple steps
First count rows in sheets using below method
private int getRowCount(Sheet currentSheet) {
int rowCount = 0;
Iterator<Row> rowIterator = currentSheet.iterator();
while(rowIterator.hasNext()) {
Row row = rowIterator.next();
if(row == null || row.getCell(0) == null || row.getCell(0).getStringCellValue().trim().equals("") || row.getCell(0).toString().trim().equals("")
|| row.getCell(0).getCellType()==Cell.CELL_TYPE_BLANK){
break;
}
else
rowCount=rowCount + 1;
}
return rowCount;
}
Then use below code in your method
Workbook workbook = WorkbookFactory.create(new File("c:/test.xls");
Sheet marksSheet = (Sheet) workbook.getSheet("Sheet1");
int zoneLastCount = 0;
if(marksSheet !=null ) {
zoneLastCount = getRowCount(marksSheet);
}
int zone = zoneLastCount-1;
int column=1
for(int i = 0; i < zone; i++) {
Row currentrow = marksSheet.getRow(i);
double year = Double.parseDouble(currentrow.getCell(columnno).toString());
int year1 = (int)year;
String str = String.valueOf(year1);
}
回答2:
Numbers in Excel are (except for a few edge cases) stored as floating point numbers. Floating point numbers in Java, when formatted as a string, are printed with a trailing decimal point, as you're seeing
Assuming what you really wanted was "give me a string that looks like what Excel shows for this cell", then do not call cell.toString(). This will not give you what you want in most cases
Instead, you need to use the DataFormatter class, which provides methods which read the Excel format rules applied to a cell, then re-creates (as best it can) those in Java
Your code should be:
Workbook wb = WorkbookFactory.create(new File("c:/test.xls");
DataFormatter fmt = new DataFormatter();
Sheet sheet = wb.getSheetAt(0);
for (Row row : sheet) {
Cell cell = row.getcell(0, Row.RETURN_BLANK_AS_NULL);
if(cell!=null) {
String value = fmt.formatCellValue(cell);
if (! value.trim().isEmpty()) {
System.out.println("Cell as string is " + value);
}
}
}
You may notice I've also fixed a bunch of other stuff as well....!
回答3:
Someone might find this hack useful:
cell.setCellType(CellType.STRING);
int value = Integer.parseInt(cell.getStringCellValue());
Remember you alter the cell type here, so be sure this does not cause any side effect. In a single-threaded app you can just read the type before and restore it after.
回答4:
You can just type cast float
to int
like :
String value = String.valueOf((int)cell.getNumericCellValue());
回答5:
Cell cell = row.getCell(cellCpt);
String cellContent = "";
if (cell != null) {
cell.setCellType(CellType.STRING);
cellContent = fmt.formatCellValue(cell);
}
回答6:
Try doing the following (to obtain a long):
long value = (long) currentCell.getNumericValue();
回答7:
// to extract the exact numerical value either integer/double
DataFormatter fmt = new DataFormatter();
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
switch (cell.getCellType()) {
case NUMERIC:
if (DateUtil.isCellDateFormatted(cell)) {
Date date = cell.getDateCellValue();
DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd");
//DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
fetchedRow.add(dateFormat.format(date));
} else {
fetchedRow.add(fmt.formatCellValue(cell));
}
rowEmpty = false;
break;
case STRING:
fetchedRow.add(cell.toString());
rowEmpty = false;
break;
case BOOLEAN:
fetchedRow.add(cell.toString());
rowEmpty = false;
break;
case FORMULA:
fetchedRow.add(Double.toString(cell.getNumericCellValue()));
rowEmpty = false;
break;
case BLANK:
fetchedRow.add("");
break;
}
}
if (!rowEmpty) {
allRows.add(fetchedRow.toArray(new String[0]));
count++;
}
if (count >= limit) {
break;
}
}
return allRows;
}
eaxmple to read limitted no.of rows on and use DataFormatter to give exact numeric value either integer/ double value. This will work.
来源:https://stackoverflow.com/questions/25771412/read-integer-from-numeric-cell-using-apache-poi-in-java