问题
I have a xml document like
<root>
<first>
First Level
<second>
second level
<third>
Third Level
</third>
</second>
<second2>
another second level
</second2>
</first>
</root>
How to convert this document with all nodes, that means if a node contains text
and child node
convert text into a child node (let's say childtext) using xquery-update
<root>
<first>
<childtext>First Level</childtext>
<second>
<childtext>second level</childtext>
<third>
Third Level
</third>
</second>
<second2>
another second level
</second2>
</first>
</root>
And here is what I tried:
let $a :=
<root>
<first>
First Level
<second>
second level
<third>
Third Level
</third>
</second>
<second2>
another second level
</second2>
</first>
</root>
return
copy $i := $a
modify (
for $x in $i/descendant-or-self::*
return (
if($x/text() and exists($x/*)) then (
insert node <childtext>
{$x/text()}
</childtext> as first into $x
(: here should be some code to delete the text only:)
) else ()
)
)
return $i
I could not delete the text which has sibling node.
回答1:
As you want to replace an element, you should simply use the replace
construct, instead of inserting the new element and deleting the old one. Seems much simpler to me:
copy $i := $a
modify (
for $x in $i/descendant-or-self::*[exists(*)]/text()
return replace node $x with <childtext>{$x}</childtext>
)
return $i
回答2:
The modified solution is from @dirkk here:
copy $i := $a
modify (
for $x in $i/descendant-or-self::*
return (
if($x/text() and exists($x/*)) then (
if(count($x/text())=1) then (
replace node $x/text() with <child> {$x/text()}</child>
) else (
for $j at $pos in 1 to count($x/text())
return
replace node $x/text()[$pos] with <child>{$x/text()[$pos]}</child>
)
) else ()
)
)
return $i
Thank you Once again.
来源:https://stackoverflow.com/questions/21087959/how-to-convert-text-inside-a-node-into-child-node-using-xquery-update