Sum of elements in an array

…衆ロ難τιáo~ 提交于 2019-12-10 13:32:09

问题


I'm working on a simple assignment for a summer java course and was just hoping you guys could take a look at my code and see if the way I did it is the best way. The purpose is to create a simple int array with at least 25 elements and use a loop to traverse it and add up all the elements. I had some issues but looks like I got it to work. After I work it out I did a little research and saw some similar stuff where people were using a For Each loop (enhanced loop). Would that be a better option? I'm kinda confused on the best ways to use that opposed to a regular for loop.

Anyway, any comments or criticism in helping me be a better programmer!

public class Traversals {

    public static void main(String[] args) {

        int absenceTotal = 0;
        // initialize array with 30 days of absences.
        int absencesArr[] = { 1, 3, 0, 9, 8, 23, 1, 
                11, 23, 5, 6, 7, 10, 1, 5,
                14, 2, 4, 0, 0, 1, 3, 2, 1, 
                1, 0, 0, 1, 3, 7, 2 };

        for (int i = 0; i < absencesArr.length; i++) {
            absencesArr[i] += absenceTotal;
            absenceTotal = absencesArr[i];
        }
        System.out.println("There were " + absenceTotal + " absences that day.");
    }
}

回答1:


Don't modify the array. I would prefer the for-each loop. And you should consider that there may be a very large number of students, so I would probably use a long for sum. And formatted output. Putting that together into something like

long sum = 0;
for(int i : absencesArr) {       
    sum += i;
}   
// System.out.println("There were " + sum + " absences that day.");   
System.out.printf("There were %d absences that day.%n", sum);



回答2:


public class Traversals {

    public static void main(String[] args) {

        int absenceTotal = 0;
        // initialize array with 30 days of absences.
        int absencesArr[] = { 1, 3, 0, 9, 8, 23, 1, 
                11, 23, 5, 6, 7, 10, 1, 5,
                14, 2, 4, 0, 0, 1, 3, 2, 1, 
                1, 0, 0, 1, 3, 7, 2 };

        for (int i = 0; i < absencesArr.length; i++) {
            // remove this
            //absencesArr[i] += absenceTotal;
            absenceTotal += absencesArr[i]; //add this
        }
        System.out.println("There were " + absenceTotal + " absences that day.");
    }
}



回答3:


In Java 8 you can use stream api:

public class Traversals {
    public static void main(String[] args) {

        int absenceTotal = 0;
        // initialize array with 30 days of absences.

        int absencesArr[] = { 1, 3, 0, 9, 8, 23, 1, 
                11, 23, 5, 6, 7, 10, 1, 5,
                14, 2, 4, 0, 0, 1, 3, 2, 1, 
                1, 0, 0, 1, 3, 7, 2 };

        absenceTotal = IntStream.of(array).sum();

        System.out.println("There were " + absenceTotal + " absences that day.");
    }
}



回答4:


shortest way i know would be :

int sum=Arrays.stream(absencesArr).sum();



回答5:


In addition to other nice contributions, I am fan of for-each loop and will typically do it in one line.

for(int i : absencesArr) absenceTotal += i;
System.out.printf("There were %d absences that day.", absenceTotal);

But in some situations when I want to have control over my Object size/length/count, I will use for loop like following example:

for (int i = 0; i < absencesArr.length; i++) absenceTotal += absencesArr[i];
System.out.printf("There were %d absences that day.", absenceTotal);

And if I need to have more then one line of codes inside the for loop or for-each loop then I will put them all inside curly brackets { more than one line of code }.



来源:https://stackoverflow.com/questions/31196967/sum-of-elements-in-an-array

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