问题
If I have a std::vector<int>
, I can obtain the index of the minimum element by subtracting two iterators:
int min_index = std::min_element(vec.begin(), vec.end()) - vec.begin();
However, with containers that don't have random access iterators, for example a std::list<int>
, this doesn't work. Sure, it is possible to do something like
int min_index = std::difference(l.begin(), std::min_element(l.begin(), l.end()));
but then I have to iterate twice through the list.
Can I get the index of the element with the minimum value with STL algorithms by only iterating once through the list or do I have to code my own for-loop?
回答1:
You'll have to write your own function, for example:
template <class ForwardIterator>
std::size_t min_element_index ( ForwardIterator first, ForwardIterator last )
{
ForwardIterator lowest = first;
std::size_t index = 0;
std::size_t i = 0;
if (first==last) return index;
while (++first!=last) {
++i;
if (*first<*lowest) {
lowest=first;
index = i;
}
}
return index;
}
来源:https://stackoverflow.com/questions/9687957/index-of-minimum-element-in-a-stdlist