问题
I want to compute ordinary least square (OLS) estimates in R without using "lm", and this for several reasons. First, "lm" also computes lots of stuff I don't need (such as the fitted values) considering that data size is an issue in my case. Second, I want to be able to implement OLS myself in R before doing it in another language (eg. in C with the GSL).
As you may know, the model is: Y=Xb+E; with E ~ N(0, sigma^2). As detailed below, b is a vector with 2 parameters, the mean (b0) and another coefficients (b1). At the end, for each linear regression I will do, I want the estimate for b1 (effect size), its standard error, the estimate for sigma^2 (residual variance), and R^2 (determination coef).
Here are my data. I have N samples (eg. individuals, N~=100). For each sample, I have Y outputs (response variables, Y~=10^3) and X points (explanatory variables, X~=10^6). I want to treat the Y outputs separately, ie. I want to launch Y linear regressions: one for output 1, one for output 2, etc. Moreover, I want to use explanatory variables one y one: for output 1, I want to regress it on point 1, then on point 2, then ... finally on point X. (I hope it's clear...!)
Here is my R code to check the speed of "lm" versus computing OLS estimates myself via matrix algebra.
First, I simulate dummy data:
nb.samples <- 10 # N
nb.points <- 1000 # X
x <- matrix(data=replicate(nb.samples,sample(x=0:2,size=nb.points, replace=T)),
nrow=nb.points, ncol=nb.samples, byrow=F,
dimnames=list(points=paste("p",seq(1,nb.points),sep=""),
samples=paste("s",seq(1,nb.samples),sep="")))
nb.outputs <- 10 # Y
y <- matrix(data=replicate(nb.outputs,rnorm(nb.samples)),
nrow=nb.samples, ncol=nb.outputs, byrow=T,
dimnames=list(samples=paste("s",seq(1,nb.samples),sep=""),
outputs=paste("out",seq(1,nb.outputs),sep="")))
Here is my own function used just below:
GetResFromCustomLinReg <- function(Y, xi){ # both Y and xi are N-dim vectors
n <- length(Y)
X <- cbind(rep(1,n), xi) #
p <- 1 # nb of explanatory variables, besides the mean
r <- p + 1 # rank of X: nb of indepdt explanatory variables
inv.XtX <- solve(t(X) %*% X)
beta.hat <- inv.XtX %*% t(X) %*% Y
Y.hat <- X %*% beta.hat
E.hat <- Y - Y.hat
E2.hat <- (t(E.hat) %*% E.hat)
sigma2.hat <- (E2.hat / (n - r))[1,1]
var.covar.beta.hat <- sigma2.hat * inv.XtX
se.beta.hat <- t(t(sqrt(diag(var.covar.beta.hat))))
Y.bar <- mean(Y)
R2 <- 1 - (E2.hat) / (t(Y-Y.bar) %*% (Y-Y.bar))
return(c(beta.hat[2], se.beta.hat[2], sigma2.hat, R2))
}
Here is my code using the built-in "lm":
res.bi.all <- apply(x, 1, function(xi){lm(y ~ xi)})
Here is my custom OLS code:
res.cm.all <- apply(x, 1, function(xi){apply(y, 2, GetResFromCustomLinReg, xi)})
When I run this example with the values given above, I get:
> system.time( res.bi.all <- apply(x, 1, function(xi){lm(y ~ xi)}) )
user system elapsed
2.526 0.000 2.528
> system.time( res.cm.all <- apply(x, 1, function(xi){apply(y, 2, GetResFromCustomLinReg, xi)}) )
user system elapsed
4.561 0.000 4.561
(And, naturally, it gets worse when increasing N, X and Y.)
Of course, "lm" has the nice property of "automatically" fitting separately each column of the response matrix (y~xi), while I have to use "apply" Y times (for each yi~xi). But is this the only reason why my code is slower? Does one of you know how to improve this?
(Sorry for such a long question, but I really tried to provide a minimal, yet comprehensive example.)
> sessionInfo()
R version 2.12.2 (2011-02-25)
Platform: x86_64-redhat-linux-gnu (64-bit)
回答1:
Have a look at the fastLm() function in the RcppArmadillo package on CRAN. There is also a similar fastLm() in RcppGSL which preceded this -- but you probably want the Armadillo-based solution. I have some slides in older presentations (on HPC with R) that show the speed gains.
Also note the hint in the help page about better 'pivoted' approaches than the straight inverse of X'X which can matter with degenerate model matrices.
回答2:
Following Marek's comment, below are the results of comparing the built-in functions "lm" and "lm.fit", my own function, "fastLm" and "fastLmPure" from the package RcppArmadillo:
> system.time( res1 <- apply(x, 1, function(xi){lm(y ~ xi)}) )
user system elapsed
2.859 0.005 2.865
> system.time( res2 <- apply(x, 1, function(xi){apply(y, 2, GetResFromCustomLinReg, xi)}) )
user system elapsed
4.620 0.004 4.626
> system.time( res3 <- apply(x, 1, function(xi){lm.fit(x=cbind(1,xi), y=y)}) )
user system elapsed
0.454 0.004 0.458
> system.time( res4 <- apply(x, 1, function(xi){apply(y, 2, fastLm, x=cbind(1,xi))}) )
user system elapsed
2.279 0.005 2.283
> system.time( res5 <- apply(x, 1, function(xi){apply(y, 2, fastLmPure, cbind(1,xi))}) )
user system elapsed
1.053 0.003 1.056
However, be careful when comparing these numbers. The differences are due not only to the different implementations, but also to which results are effectively computed:
> names(res1$p1)
[1] "coefficients" "residuals" "effects" "rank"
[5] "fitted.values" "assign" "qr" "df.residual"
[9] "xlevels" "call" "terms" "model"
> # res2 (from my own custom function) returns the estimate of beta, its standard error, the estimate of sigma and the R^2
> names(res3$p1)
[1] "coefficients" "residuals" "effects" "rank"
[5] "fitted.values" "assign" "qr" "df.residual"
> names(res4$p1$out1)
[1] "coefficients" "stderr" "df" "fitted.values"
[5] "residuals" "call"
> names(res5$p1$out1)
[1] "coefficients" "stderr" "df"
For instance, we may prefer to use "lm.fit" over "lm", but if we need the R^2, we will have to compute it by ourselves. Idem, we may want to use "fastLm" over "lm", but if we want the estimate of sigma, we will have to compute it by ourselves. And computing such things with a custom R function may not be very efficient (compare to what is done by "lm").
In the light of all this, I will keep using "lm" for the moment, but indeed Dirk's comment about "fastLm" is good advice (that's why I chose his answer, as it should be of interest for other people).
来源：https://stackoverflow.com/questions/6234652/how-to-compute-minimal-but-fast-linear-regressions-on-each-column-of-a-response