问题
I have an array I'm getting back from scandir, but it contains "." and ".." and I don't want it to.
My code:
$indir = scandir('../pages');
$fileextensions = array(".", "php", "html", "htm", "shtml");
$replaceextensions = str_replace($fileextensions, "", $indir);
I am doing a string replace on the file extensions, thus causing [0] and [1] to appear empty, but they are "." and ".."
array(4) {
[0]=>
string(0) ""
[1]=>
string(0) ""
[2]=>
string(4) "test"
[3]=>
string(4) "home"
}
How would I remove the "." and ".." from the array?
回答1:
You can use array_filter.
$indir = array_filter(scandir('../pages'), function($item) {
return !is_dir('../pages/' . $item);
});
Note this filters out all directories and leaves only files and symlinks. If you really want to only exclude only files (and directories) starting with ., then you could do something like:
$indir = array_filter(scandir('../pages'), function($item) {
return $item[0] !== '.';
});
回答2:
Fastest way to remove dots as files in scandir
$files = array_slice(scandir('/path/to/directory/'), 2);
From the PHP Manual
回答3:
array_diff will do what you're looking for:
$indir = scandir('../pages');
$fileextensions = array(".", "php", "html", "htm", "shtml");
$indir = array_diff($indir, array('.', '..'));
$replaceextensions = str_replace($fileextensions, "", $indir);
http://php.net/manual/en/function.array-diff.php
回答4:
I am aware erknrio provided an answer for this, but here is a cleaner way of getting an array of files without directories (modified to be more efficient):
$dirPath = 'dashboard';
$dir = scandir($dirPath);
foreach($dir as $index => &$item)
{
if(is_dir($dirPath. '/' . $item))
{
unset($dir[$index]);
}
}
$dir = array_values($dir);
回答5:
You can use this snippet. It returns just files in directory:
function only_files($dir_element) {
if (!is_dir($dir_element)) {
return $dir_element;
}
}
function givemefiles($dir) {
$scanned_dir = scandir($dir);
return array_filter($scanned_dir, "only_files");
}
$dir_path = '../pages';
givemefiles($dir_path);
echo "<pre>";
var_dump($scanned_dir);
echo "</pre>";
回答6:
simply use preg_replace to remove all kind of hidden's file from directory
$files = array(".", "..", "html", ".~html", "shtml");
$newfiles = preg_grep('/^([^.])/', scandir($files));
来源:https://stackoverflow.com/questions/14680121/include-just-files-in-scandir-array