SQL Computation of Cosine Similarity

杀马特。学长 韩版系。学妹 提交于 2019-12-06 05:15:14

问题


Suppose you have a table in a database constructed as follows:

create table data (v int, base int, w_td float);
insert into data values (99,1,4);
insert into data values (99,2,3);
insert into data values (99,3,4);
insert into data values (1234,2,5);
insert into data values (1234,3,2);    
insert into data values (1234,4,3);

To be clear select * from data should output:

v   |base|w_td
--------------
99  |1   |4.0
99  |2   |3.0
99  |3   |4.0
1234|2   |5.0
1234|3   |2.0
1234|4   |3.0

Note that since the vectors are stored in a database, we need only store the non-zero entries. In this example, we only have two vectors $v_{99} = (4,3,4,0)$ and $v_{1234} = (0,5,2,3)$ both in $\mathbb{R}^4$.

The cosine similarity of those vectors should be $\displaystyle \frac{23}{\sqrt{41 \cdot 38}} = 0.5826987807288609$.

How do you compute the cosine similarity using nearly only SQL?

I say nearly because you will need the sqrt function which is not always provided in basic SQL implementations, for example it is not in sqlite3!


回答1:


with norms as (
    select v,
        sum(w_td * w_td) as w2
    from data
    group by v
)
select 
    x.v as ego,y.v as v,nx.w2 as x2, ny.w2 as y2,
    sum(x.w_td * y.w_td) as innerproduct,
    sum(x.w_td * y.w_td) / sqrt(nx.w2 * ny.w2) as cosinesimilarity
from data as x
join data as y
    on (x.base=y.base)
join norms as nx
    on (nx.v=x.v)
join norms as ny
    on (ny.v=y.v)
where x.v < y.v
group by 1,2,3,4
order by 6 desc

yields

ego|v   |x2  |y2  |innerproduct|cosinesimilarity
--------------------------------------------------
99 |1234|41.0|38.0|23.0        |0.5826987807288609


来源:https://stackoverflow.com/questions/42310655/sql-computation-of-cosine-similarity

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