How do I find the display size of my system in Emacs?

问题

I use the same .emacs across multiple machines, operating systems and platforms. I would like the default frame size of Emacs upon invocation to be relative to the available screen size (e.g. 96 lines work very well on a 1600x1200 desktop screen, but on an 1280x800 laptop I need to specify no more than 68 lines).

Is there an emacs-lisp expression that returns the width & height of the system's screen?

Update: I just found a similar question, but for some reason neither (x-display-pixel-width) nor (display-pixel-width) can be found in my GNU Emacs 23.2 on Windows XP system. Continuing to research...

回答1:

I'm running Gnu Emacs 23.2.1 on XP Pro, and the functions

(x-display-pixel-width)

and

(x-display-pixel-height)

are both working just fine. They are a part of the c source, and should be present.

You CAN run emacs outside of a terminal it trust?

Here's the documentation from my current emacs:

x-display-pixel-height is a built-in function in `C source code'.

(x-display-pixel-height &optional TERMINAL)

Return the height in pixels of the X display TERMINAL. The optional argument TERMINAL specifies which display to ask about. TERMINAL should be a terminal object, a frame or a display name (a string). If omitted or nil, that stands for the selected frame's display.

Also, I have a entire library of convenience functions to help with sizing and moving the emacs frame, if you interested.

回答2:

I'm doing it a poor way, for a somewhat-older version.

(tool-bar-mode nil)

(mapc (lambda (x) (add-to-list 'default-frame-alist x))
   (list
          (cons 'top 0) (cons 'left 0)
          (cons 'font "-outline-Courier New-normal-r-normal-normal-11-82-96-96-c-*-iso10646-1")
          (cons 'height 67) (cons 'width 176)
))

The default frame is built after .emacs runs, from the default-frame-alist. I've never heard of the initial-frame-alist.

回答3:

Thanks to the answer and comments by Chris and Scott, I managed to come up with the following working line in my .emacs:

(set-frame-size  (selected-frame)  96 (/ (* (x-display-pixel-height) 46) 600) )

It works well when I do eval-buffer on the .emacs, but when I double-click Windows XP's Emacs shortcut, this statement is ignored completely.

I know that (selected-frame) is not the (initial-frame) so I tried this too:

(setq initial-frame-alist
    '((top . 1) (left . 288) (width . 96) (height . (/ (* (x-display-pixel-height) 46) 600))))

But it works only when I do eval-buffer on the read .emacs. It doesn't work when Emacs is started (either from the command line or by double-clicking its shortcut). Weird.

Update: I ended up setting the initial size in the invocation command in the shortcut's Target field:

C:\emacs-23.2\bin\runemacs.exe -geometry 96x78+240+0

An ugly solution, I know, but currently that's the only solution that does the trick.

来源：https://stackoverflow.com/questions/3514299/how-do-i-find-the-display-size-of-my-system-in-emacs

标签

emacs

pixels

screen-size