问题
I am trying to find the means, not including NAs, for multiple columns withing a dataframe by multiple groups
airquality <- data.frame(City = c("CityA", "CityA","CityA",
"CityB","CityB","CityB",
"CityC", "CityC"),
year = c("1990", "2000", "2010", "1990",
"2000", "2010", "2000", "2010"),
month = c("June", "July", "August",
"June", "July", "August",
"June", "August"),
PM10 = c(runif(3), rnorm(5)),
PM25 = c(runif(3), rnorm(5)),
Ozone = c(runif(3), rnorm(5)),
CO2 = c(runif(3), rnorm(5)))
airquality
So I get a list of the names with the number so I know which columns to select:
nam<-names(airquality)
namelist <- data.frame(matrix(t(nam)));namelist
I want to calculate the mean by City and Year for PM25, Ozone, and CO2. That means I need columns 1,2,4,6:7)
acast(datadf, year ~ city, mean, na.rm=TRUE)
But this is not really what I want because it includes the mean of something I do not need and it is not in a data frame format. I could convert it and then drop, but that seems like a very inefficient way to do it.
Is there a better way?
回答1:
We can use dplyr
with summarise_at
to get mean
of the concerned columns after grouping by the column of interest
library(dplyr)
airquality %>%
group_by(City, year) %>%
summarise_at(vars("PM25", "Ozone", "CO2"), mean)
回答2:
The summarise_at
solution by Colin is simplest, but of course there are several.
Here is another solution, using tidyr
to rearrange and calculate the mean:
airquality %>%
select(City, year, PM25, Ozone, CO2) %>%
gather(var, value, -City, -year) %>%
group_by(City, year, var) %>%
summarise(avg = mean(value, na.rm=T)) %>% # can stop here if you want
spread(var, avg) # optional to make this into a wider table
# A tibble: 8 x 5
# Groups: City, year [8]
City year CO2 Ozone PM25
* <fctr> <fctr> <dbl> <dbl> <dbl>
1 CityA 1990 0.275981522 0.19941717 0.826008441
2 CityA 2000 0.090342153 0.50949094 0.005052771
3 CityA 2010 0.007345704 0.21893117 0.625373926
4 CityB 1990 1.148717447 -1.05983482 -0.961916973
5 CityB 2000 -2.334429324 0.28301220 -0.828515418
6 CityB 2010 1.110398814 -0.56434523 -0.804353609
7 CityC 2000 -0.676236740 0.20661529 -0.696816058
8 CityC 2010 0.229428142 0.06202997 -1.396357288
回答3:
You should try dplyr::mutate_at
:
library(dplyr)
airquality %>%
group_by(City, year) %>%
summarise_at(.vars = c("PM10", "PM25", "Ozone", "CO2"), .funs = mean)
# A tibble: 8 x 6
# Groups: City [?]
City year PM10 PM25 Ozone CO2
<fctr> <fctr> <dbl> <dbl> <dbl> <dbl>
1 CityA 1990 0.004087379 0.5146409 0.44393422 0.61196671
2 CityA 2000 0.039414194 0.8865582 0.06754322 0.69870187
3 CityA 2010 0.116901563 0.6608619 0.51499227 0.32952099
4 CityB 1990 -1.535888778 -0.9601897 1.17183649 0.08380664
5 CityB 2000 0.226046487 0.4037230 0.86554997 -0.05698204
6 CityB 2010 -0.824719956 0.1508471 0.32089806 -0.12871853
7 CityC 2000 -0.824509111 -0.6928741 0.85553837 0.12137923
8 CityC 2010 -1.626150294 1.5176198 0.21183149 -0.63859910
回答4:
So I tested the comments above and added more replication to the original dataset because I wanted to calculate the average by city and by year. Here is the updated dataset
airquality <- data.frame(City = c("CityA", "CityA","CityA","CityA",
"CityB","CityB","CityB","CityB",
"CityC", "CityC", "CityC"),
year = c("1990", "2000", "2010", "2010",
"1990", "2000", "2010", "2010",
"1990", "2000", "2000"),
month = c("June", "July", "August", "August",
"June", "July", "August","August",
"June", "August", "August"),
PM10 = c(runif(6), rnorm(5)),
PM25 = c(runif(6), rnorm(5)),
Ozone = c(runif(6), rnorm(5)),
CO2 = c(runif(6), rnorm(5)))
airquality
Of the answers above, AK run and Colin worked.
来源:https://stackoverflow.com/questions/46330352/means-multiple-columns-by-multiple-groups