Problem Description:
Some Websites impose certain rules for passwords. Write a method that checks whether a string is a valid password. Suppose the password rule is as follows:
- A password must have at least eight characters.
- A password consists of only letters and digits.
- A password must contain at least two digits.
Write a program that prompts the user to enter a password and displays "valid password" if the rule is followed or "invalid password" otherwise.
This is what I have so far:
import java.util.*;
import java.lang.String;
import java.lang.Character;
/**
* @author CD
* 12/2/2012
* This class will check your password to make sure it fits the minimum set requirements.
*/
public class CheckingPassword {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Please enter a Password: ");
String password = input.next();
if (isValid(password)) {
System.out.println("Valid Password");
} else {
System.out.println("Invalid Password");
}
}
public static boolean isValid(String password) {
//return true if and only if password:
//1. have at least eight characters.
//2. consists of only letters and digits.
//3. must contain at least two digits.
if (password.length() < 8) {
return false;
} else {
char c;
int count = 1;
for (int i = 0; i < password.length() - 1; i++) {
c = password.charAt(i);
if (!Character.isLetterOrDigit(c)) {
return false;
} else if (Character.isDigit(c)) {
count++;
if (count < 2) {
return false;
}
}
}
}
return true;
}
}
When I run the program it only checks for the length of the password, I cannot figure out how to make sure it is checking for both letters and digits, and to have at least two digits in the password.
You almost got it. There are some errors though:
- you're not iterating over all the chars of the password (
i < password.length() - 1
is wrong) - you start with a digit count of 1 instead of 0
- you make the check that the count of digits is at least 2 as soon as you meet the first digit, instead of checking it after you have scanned all the characters
Suppose a valid password has:
- 8 or more characters, but not more than 16 characters
- one or more uppercase characters
- one or more lowercase characters
- one or more digits
- one or more special characters (like $, @, or !)
Code:
import java.util.Scanner;
public class Password {
public static void main(String[] args) {
// TODO Auto-generated method stub
int min =8;
int max=16;
int digit=0;
int special=0;
int upCount=0;
int loCount=0;
String password;
Scanner scan = new Scanner(System.in);
System.out.println(" Enter Your Password:");
password = scan.nextLine();
if(password.length()>=min&&password.length()<=max){
for(int i =0;i<password.length();i++){
char c = password.charAt(i);
if(Character.isUpperCase(c)){
upCount++;
}
if(Character.isLowerCase(c)){
loCount++;
}
if(Character.isDigit(c)){
digit++;
}
if(c>=33&&c<=46||c==64){
special++;
}
}
if(special>=1&&loCount>=1&&upCount>=1&&digit>=1){
System.out.println(" Password is good:");
}
}
if(password.length()<min){
for(int i =0;i<password.length();i++){
char c = password.charAt(i);
if(Character.isLowerCase(c)){
loCount++;
}
}
if(loCount>0){
System.out.println(" Password must be atleat "+min+" characters:");
System.out.println(" You need atleast one upper case chracter:");
System.out.println(" You need atleast one digit:");
System.out.println(" You need atleast one special chracter:");
}
}
else if(password.length()<min&&upCount>1){
for(int i =0;i<password.length();i++){
char c =password.charAt(i);
if(Character.isLowerCase(c)){
loCount++;
}
if(Character.isUpperCase(c)){
upCount++;
}
}
if(loCount>0&&upCount>0){
System.out.println(" Password must be atleast "+min+" chracters:");
System.out.println(" You need atleast one digit:");
System.out.println(" You need atleast one special chracter:");
}
}
if(password.length()>max||password.length()>=max&&upCount>1&&loCount>1&&digit>1){
System.out.println(" Password is too long.Limit is "+max+" chracters:");
System.out.println(" You need atleast one special chracter:");
}
if(password.length()>=min&&password.length()<=max&&loCount>0&&upCount>0&&digit>0&&special==0){
System.out.println(" You need atleast a special chracter");
}
if(password.length()>=min&&password.length()<=max&&loCount>0&&upCount>0&&digit==0&&special==0){
System.out.println(" You need atleast one digit:");
System.out.println(" You need atleast one special chracter:");
}
}
}
As previously answered, you should chek all the password characters first. Count your digits and finally check if count is smaller than 2. Here is the referring code.
if (password.length() < 8) {
return false;
} else {
char c;
int count = 0;
for (int i = 0; i < password.length(); i++) {
c = password.charAt(i);
if (!Character.isLetterOrDigit(c)) {
return false;
} else if (Character.isDigit(c)) {
count++;
}
}
if (count < 2) {
return false;
}
}
return true;
}
public void run()
{
String password= readLine("Insert Password: ");
boolean len= true;
boolean letter= true;
boolean twodig= true;
if (password.length() < 8) {
len = false;
} else {
char c;
int count = 0;
for (int i = 0; i < password.length(); i++) {
c = password.charAt(i);
if (!Character.isLetterOrDigit(c)) {
letter = false;
} else if (Character.isDigit(c)) {
count++;
}
}
if (count < 2) {
twodig = false;
}
}
if(len ==true && letter == true && twodig == true)
{
System.out.println("This password is valid ");
}
else
{
System.out.println("This password is invalid");
}
}
package Method;
/* 2. Write a Java method to check whether a string is a valid password. Password rules: A password must have at least ten characters. A password consists of only letters and digits. A password must contain at least two digits.
Expected Output:
- A password must have at least eight characters.
- A password consists of only letters and digits.
- A password must contain at least two digits
Input a password (You are agreeing to the above Terms and Conditions.): abcd1234
Password is valid: abcd1234 */
public class CheckPassword {
public static String password;
public static int disitCounter = 0;
public static boolean isValid(String password) {
if (password.length() >= 10 ) {
for(int index = 0; index < password.length(); index++) {
char passChar = password.charAt(index);
if (!Character.isLetterOrDigit(passChar)) {
return false;
}
else {
if (Character.isDigit(passChar)) {
disitCounter++;
}
}
}
}
if(disitCounter < 2) {
return false;
}
return true;
}
public static void main(String[] args) {
password = "abcdefgh1w3";
if(isValid(password)) {
System.out.print("It is a valid password");
}
else {
System.out.print("It is a invalid password");
}
}
}
package com.parag;
/*
* @author Parag Satav
*/
public boolean check(String password) {
boolean flagUppercase = false;
boolean flagLowercase = false;
boolean flagDigit = false;
boolean flag = false;
if (password.length() >= 10) {
for (int i = 0; i < password.length(); i++) {
if (!Character.isLetterOrDigit(password.charAt(i))) {
return false;
}
if (Character.isDigit(password.charAt(i)) && !flagDigit) {
flagDigit = true;
}
if (Character.isUpperCase(password.charAt(i)) && !flagUppercase) {
flagUppercase = true;
}
if (Character.isLowerCase(password.charAt(i)) && !flagLowercase) {
flagLowercase = true;
}
}
}
if (flagDigit && flagUppercase && flagLowercase) {
flag = true;
System.out.println("Success..");
} else
System.out.println("Fail..");
return flag;
}
来源:https://stackoverflow.com/questions/13674449/checking-password-code