问题
In this example; i am trying to create a jQuery animation with css3 rotate property. I can manage this animation with css3 transition
and jQuery css()
but i want to do this with jQuery animate()
for rotating deg value according to my jQuery variatons.
Is it possible use animate with css3 property value with jQuery 1.8.0?
Here is jsFiddle to inspect.
jQuery:
var rotateVal = 90;
//this method isn't working
$('.red').animate({
'transform':'rotate('+rotateVal+'deg)'
},500);
//this way works but i don't want to do this with transitions
$('.black').css({
'transform':'rotate('+rotateVal+'deg)',
'transition':'1s'
});
html:
<span class="black"></span>
<span class="red"></span>
Edit: Vendor prefixes removed, like -webkit-
. Thanks to Kevin B.
回答1:
It is possible, but it isn't easy.
var red = $(".red"),
rotateVal = 90;
$("<div />").animate({
height: rotateVal
},{
duration: 500,
step: function(now){
red.css('transform','rotate('+now+'deg)');
}
});
This basically creates a fake animation of a detached div, then on each step, updates the rotation of the target div.
Edit: Oops! wrong argument order. Here's a demo. http://jsfiddle.net/qZRdZ/
note that in 1.8.0 i don't think you need to specify all the vendor prefixes.
Using this method, you can animate almost anything as long as you keep in mind that things like +=
and -=
won't work properly unless coded for.
Update: Here's a combination of my solution and cuzzea's solution abstracted behind a function. http://jsfiddle.net/qZRdZ/206/
$.fn.rotate = function(start, end, duration) {
console.log(this);
var _this = this;
var fakeDiv = $("<div />");
_this.promise().done(function(){
_this.animate({"a":end},{duration:duration});
fakeDiv.css("height", start).animate({
height: end
}, {
duration: duration,
step: function(now) {
_this.css("transform", "rotate(" + now + "deg)");
},
complete: function() {
fakeDiv.remove();
}
});
});
return _this;
};
var red = $('.red');
red.click(function() {
if ( !$(this).is(':animated') ) {
red.rotate(45,135,500);
setTimeout(function(){
red.rotate(135,190,500);
},750);
setTimeout(function(){
red.rotate(190,45,500);
},1500);
}
});
});
回答2:
Kevin is corect, almost. :)
Here is working jsFiddle.
You don't have to use another element and height, you can do something like:
var red = $('.red'),
max_rot = 45,
start_from = 90;
red.css({a:0}).animate(
{'a':1},
{ step: function(value,tweenEvent)
{
rotateVal = start_from + max_rot * value;
red.css({
'transform':'rotate('+rotateVal+'deg)',
});
}
},
1000);
The ideea is simple. First we create a bogus css property 'a' and set it to 0, and then we animate it to 1, so the step function will give you a value of 0 to 1 that you can use to set the custom transform.
回答3:
An alternative method would be to use jQuery to change the dom to something that css would respond to.
We can set our css to look like this:
.object {
-webkit-transition:all .4s;
-moz-transform:all .4s;
-o-transform:all .4s;
-ms-transform:all .4s;
transform:all .4s;
}
.object[data-rotate="false"] {
-webkit-transform:rotate(0deg);
-moz-transform:rotate(0deg);
-o-transform:rotate(0deg);
-ms-transform:rotate(0deg);
transform:rotate(0deg);
}
.object[data-rotate="true"] {
-webkit-transform:rotate(90deg);
-moz-transform:rotate(90deg);
-o-transform:rotate(90deg);
-ms-transform:rotate(90deg);
transform:rotate(90deg);
}
Our jQuery would look like this:
$('#trigger').live('click',function(){
if($('.object').attr('data-rotate') = true) {
$('.object').attr('data-rotate',false);
}
else {
$('.object').attr('data-rotate', true);
}
});
Obviously, the browser has to support the ability to transform whatever animation you want to run, so its its hit or miss depending on the type of animation, but its nicer to work with if you have a ton of stuff going on or you have some children you want to animate concurrently.
Example fiddle: http://jsfiddle.net/ddhboy/9DHDy/1/
来源:https://stackoverflow.com/questions/12062818/how-to-combine-jquery-animate-with-css3-properties-without-using-css-transitions