How to validate both Chinese (unicode) and English name?

Question

I have a multilingual website (Chinese and English).

I like to validate a text field (name field) in javascript. I have the following code so far.

var chkName = /^[characters]{1,20}$/;

if( chkName.test("[name value goes here]") ){
  alert("validated");
}

the problem is, /^[characters]{1,20}$/ only matches English characters. Is it possible to match ANY (including unicode) characters? I used to use the following regex, but I don't want to allow spaces between each characeters.

/^(.+){1,20}$/

Answer 1

You might check out Javascript + Unicode regexes and do some research to find exactly which ranges of characters you want to allow:

See What's the complete range for Chinese characters in Unicode?

After reading those two and a little extra research you should be able to find appropriate values to complete something like: /^[-'a-z\u4e00-\u9eff]{1,20}$/i

Answer 2

Take a look at Regex Unicode blocks.

You can use this to take care of CJK names.

Answer 3

As of 2018, there is new syntax in JavaScript to match Chinese or any other non-ASCII scripts:

const REGEX = /(\p{Script=Hani})+/gu; // note the 'u'
'你好'.match(REGEX);
// ["你好"]

The trick is to use \p and use the right script name, Hani stands for Han script (Chinese). The full list of scripts is here: http://unicode.org/Public/UNIDATA/PropertyValueAliases.txt

To match both Chinese and English you just expand it a bit, for example:

const REGEX = /([A-Za-z]|\p{Script=Hani})+/gu;
// does not match accented letters though

Answer 4

var chkName = /\s/;

function check(name) {

    document.write("<br />" + name + " is ");

    if (!chkName.test(name)) {
        document.write("okay");
    } else {
        document.write("invalid");
    }

}

check("namevaluegoeshere");

check("name value goes here");

This way you just check if there's any white space in the name.

demo @ http://jsfiddle.net/roberkules/U3q5W/

Answer 5

I have done some work on validating Chinese names using XRegExp. The core code is XRegExp("^((?![\\p{InKangxi_Radicals}\\p{InCJK_Radicals_Supplement}\\p{InCJK_Symbols_and_Punctuation}])\\p{Han}){2,4}$","u")

See jsfiddle.net/coas/4djhso1y