I have a list which gets one element each time user opens a file. I need to create a button with the file's name (element from the list), each time this file is appended to a list, and put this button into a scroll-area.
The problem is that I always have only one button, that just changes its name:
filenames = []
def addfiles():
fileName = QtGui.QFileDialog.getOpenFileName()
fileDirectory = unicode(fileName)
global filenames
filenames.append(fileDirectory)
button = QtGui.QPushButton(os.path.basename(fileDirectory))
window.scrollArea.setWidget(button)
I know that the problem is that I add the same object (button) to the scroll-area, but I don't know how to fix it.
The Problem is not that you add the same button, but that you sort of replace the Widget in the scrollArea.
A better way would be to create a QHBoxLayout and than add the buttons to the layout.
filenames = []
lay = QtGui.QHboxLayout()
window.scrollArea.setLayout(lay)
def addfiles():
fileName= QtGui.QFileDialog.getOpenFileName()
fileDirectory = unicode(fileName)
global filenames
filenames.append(fileDirectory)
button = QtGui.QPushButton(os.path.basename(fileDirectory))
lay.addWidget(button)
In a sort of that way it should work. Here is a small working example:
from PyQt4 import QtGui
import sys
filenames = []
class TestGui(QtGui.QWidget):
""" A Fast test gui show how to create buttons in a ScrollArea"""
def __init__(self):
super(TestGui, self).__init__()
self.lay = QtGui.QHBoxLayout()
self.sA = QtGui.QScrollArea()
self.sA_lay = QtGui.QVBoxLayout()
self.sA.setLayout(self.sA_lay)
self.closeGui = QtGui.QPushButton("Close")
self.add_file_button = QtGui.QPushButton("Add File")
self.lay.addWidget(self.closeGui)
self.lay.addWidget(self.add_file_button)
self.lay.addWidget(self.sA)
self.setLayout(self.lay)
self.connect_()
self.show()
def connect_(self):
self.add_file_button.clicked.connect(self.__add_file_to_list)
self.closeGui.clicked.connect(self.close)
return
def __add_file_to_list(self):
fname = QtGui.QFileDialog.getOpenFileName()
global filenames
filenames.append(fname)
button = QtGui.QPushButton(fname)
self.sA_lay.addWidget(button)
return
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
tg = TestGui()
sys.exit(app.exec_())
The problem is that you're not adding a layout to the scrollLayout, you're setting the scrollArea's widget:
#!/usr/bin/env python
import os, sys
from PyQt4 import QtCore, QtGui
filenames = []
class Window(QtGui.QMainWindow):
def __init__(self, parent=None):
super(Window, self).__init__(parent)
self.centralwidget = QtGui.QWidget(self)
self.verticalLayout = QtGui.QVBoxLayout(self.centralwidget)
self.scrollArea = QtGui.QScrollArea(self.centralwidget)
self.scrollArea.setWidgetResizable(True)
self.scrollAreaWidgetContents = QtGui.QWidget(self.scrollArea)
self.scrollArea.setWidget(self.scrollAreaWidgetContents)
self.verticalLayout.addWidget(self.scrollArea)
self.setCentralWidget(self.centralwidget)
# create a layout for your scrollarea
self.formLayout = QtGui.QFormLayout(self.scrollAreaWidgetContents)
self.addFiles()
def addFiles(self):
global filenames
filenames.append("~/files/newFile.txt")
button = QtGui.QPushButton(os.path.basename(filenames[-1]))
self.formLayout.addWidget(button)
来源:https://stackoverflow.com/questions/36137791/how-to-create-a-button-for-each-element-in-a-list-and-put-it-in-a-scroll-area