问题
Couldn't the diamond problem be resolved just by using the first inherited declaration found? I mean,
public class A { public virtual int getInt(); }; public class B : public A { public int getInt() {return 6;} }; public class C : public A { public int getInt() {return 7;} }; public class D: public B, public C {};
for class D
, since B
is listed first, couldn't we just by default (when it's ambiguous) use B::getInt()
if D::getInt()
is called? Kind of how the PATH environment variable works in UNIX and other OS's; if two things exist with the same name in different locations in the PATH variable, then the first location shall be used by default (unless otherwise qualified).
Edit: by 'first' inherited declaration found I mean according to simple left-to-right depth-first order
Edit#2: Just updated the above implementation to be more diamond-like.
回答1:
It's a very buggy solution. Think what will happen in the following case:
public class A {
public int getInt() {return 5;}
public float getFloat() {return 5.0;}
};
public class B {
public int getInt() {return 6;}
public float getFloat() {return 6.0;}
};
public class C {
public int getInt() {return 7;}
public float getFloat() {return 7.0;}
};
public class D: public A, public B, public C {}
Suppose that one will want D::getInt
to return 5 while another developer wants D::getFloat
to return 7.0 (thus, different functions resolved to different ancestors). The second developer will change the order of inheritance and a bug will creep in all code paths depending on getInt
.
回答2:
This is not a diamond problem. C++ compiler is specific about all its syntax, if there is any ambiguity it will always throw error.
Here your A::getInt()
, B::getInt()
and C::getInt()
are ambiguous when you call simply d.getInt()
.
Edit:
In your edited question, still compiler doesn't evaluate from the inheritance, because some programmers may really need to have different copies of A
==> 1st via class B
and 2nd via class C
. Note that so called diamond problem is a problem characterized by humans. For C++ compiler, it's just one more pattern.
In C++ philosophy, you are not restricted to only one paradigm or pattern. You can choose to have multiple inheritance of your choice.
来源:https://stackoverflow.com/questions/6704332/c-resolving-the-diamond-problem