zend-form

问题 So the thing is I have a form in page A which is being submitted at page B. After validating the form at page B, it should redirect back to page A and show the form with the possible errors that occurred. What's the best way to achieve this? Is it smart to temporary put the whole form object in the session? Or is there a more elegant solution? 回答1: Why not validate it on page A, and then forward to page B if it's valid? That way you don't have to do any ugly hacks. 回答2: The correct way is to

问题 I have some radio buttons in a form: <div id="data_id-block"> <dt id="data_id-label"><label class="required">Data</label></dt> <dd id="data_id-element"> <label for="data_id-1"> <input type="radio" name="data_id" id="data_id-1" value="1" />test 1 </label><br /> <label for="data_id-2"> <input type="radio" name="data_id" id="data_id-2" value="2" />test 2 </label><br /> <label for="data_id-4"> <input type="radio" name="data_id" id="data_id-4" value="4" /> Test Data </label><br /> <label for="data

问题 (I follow this post to got the logic how to use Zend_Form without using decorators.) within the action I create Zend_Form object and assigned the form to the view before rendering it: public function indexAction() { $form = new Zend_Form(); $form->setAction('process') ->setMethod('post'); $username = $form->createElement('text','username'); $username->addValidator('alnum') ->setRequired(true) ->addFilter('StringtoLower'); $description = $form->createElement('textarea','description');

问题 Zend Captcha generates 3 elements together are captcha image, hidden input element, input text box for captcha code respectively and places them side by side without any separator. I want to decorate captcha image tag only in captcha element being generated by zend form captcha. And leave input elements intact. I don't want to create custom decorator class for it. Is there any way to do this? I delve into zend decorator where I see $_separator variable. Can it be helpful? Please help. 回答1:

问题 Anyone have a good and complete example for many to many relation using ZF2 and Doctrine 2, especially when using ObjectMultiCheckBox ? I found this tutorial - https://github.com/doctrine/DoctrineModule/blob/master/docs/hydrator.md but it don't explain how to do a many to many relation. 回答1: K so I figured out how todo this eventually after realizing the hydrator wasn't binding associations and I had to create the link. I'm going to put a full blog post up explaining it but in case you're

问题 I create my forms via extending Zend_Form. And I use one Form for addAction() and editAction() . When I want to remove Elements within the editing process I can do so easily via $form->removeElement('x') . But what would be the best approach on removing a field from the validator? 1) Removing and Adding the newly set validator //Controllers editAction() $form->removeValidator('Db_NoRecordExists'); $form->addValidator('Db_NoRecordExists', true, array( 'table'=>'table', 'field'=>'field',

问题 So i got a ZF2 application, got a Form and a InputFilter in the InputFilter i have: $this->add( array( 'name' => 'email', 'required' => true, 'validators' => array( array( 'name' => 'EmailAddress' ), array( 'name' => 'DoctrineModule\Validator\NoObjectExists', 'options' => array( 'object_repository' => $sm->get('doctrine.entitymanager.orm_default')->getRepository('YrmUser\Entity\User'), 'fields' => 'email' ), ), ), ) ); works great, however when i edit a existing object and save it the

问题 I have a Zend Framework form that has two submit buttons $changes = new Zend_Form_Element_Submit('save_changes'); $changes->setLabel('Save Changes'); $delete = new Zend_Form_Element_Submit('delete'); $delete->setLabel('Delete'); Which renders HTML like such: <input type="submit" name="save_changes" id="user_save_changes" value="Save Changes" > <input type="submit" name="delete" id="user_delete" value="Delete" > In the controller, how do I determine which button the user pressed? 回答1: In your

问题 Zend_Form:: When should be form created in view and not in controller? option 1 - form created in controller and passed to view (usually used) controller: $form=new MyForm(); $this->view->form=$form; view: echo $this->form; option 2 - form created in view directly (looks better to me because form its subpart of view) view: $form=new MyForm(); echo $this->form; Thanks 回答1: In short: newer in view . You may eventually: create view helper for complex tasks (and call the helper in view $this-

问题 I have simple class which extends Zend_Form with 2 elements: class Application_Form_Player extends Zend_Form { public function init() { $this->addElement('text', 'firstName', array( 'label' => $this->getView()->translate('First name') . ' (' . $this->getView()->translate('imaginary') . ')', 'required' => true, 'filters' => array('StringTrim'), 'validators' => array(array('StringLength', false, array(1, 256))) ) ); $this->addElement('text', 'lastName', array( 'label' => $this->getView()-