xstream | 易学教程

Generate Java class from XML file, using XStream

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问题 I have many xml files and I would like to use XStream to manage them. Is it possible to generate java classes corresponding to my xml files using XStream? 回答1: XStream is a software to serialize and deserialize a Java Object to and from XML. XStream uses Reflection for this. The class of the objects involved has to exist beforehand. JAXB is a binding framework, which too does serialization and deserialization. JAXB has annotations to do this work. Bundled with the framework come tools to

customising serialisation of java collections using xstream

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问题 I have an object that needs to be serialised as XML, which contains the following field: List<String> tags = new List<String>(); XStream serialises it just fine (after some aliases) like this: <tags> <string>tagOne</string> <string>tagTwo</string> <string>tagThree</string> <string>tagFour</string> </tags> That's OK as far as it goes, but I'd like to be able to rename the <string> elements to, say, <tag> . I can't see an obvious way to do that from the alias documentation on the XStream site.

Xstream no-args constructor error

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问题 I'm getting the following error when it tries to create an instance of 'Transacao' `Error: Cannot construct br.com.cbmp.ecommerce.resposta.Transacao as it does not have a no-args constructor : Cannot construct br.com.cbmp.ecommerce.resposta.Transacao as it does not have a no-args constructor ` ---- Debugging information ---- message : Cannot construct br.com.cbmp.ecommerce.resposta.Transacao as it does not have a no-args constructor cause-exception : com.thoughtworks.xstream.converters

XStream - Root as a collection of objects

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问题 I'm consuming an XML payload that looks something like this (for a more comprehensive example, check out : http://api.shopify.com/product.html ). <products type="array"> <product> ... </product> <product> ... </product> </products> Now currently my code does work, but its doing something that appears to be really really "wrong" - namely it associates the "products" with List.class. So the relevant code looks like the following: xstream.alias( "products", List.class ); xstream.alias( "product"

XStream Alias of List root elements

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问题 I want to be able to alias the root list element depending upon what type of objects are contained in the list. For example, this is my current output: <list> <coin>Gold</coin> <coin>Silver</coin> <coin>Bronze</coin> </list> And this is what I want it to look like: <coins> <coin>Gold</coin> <coin>Silver</coin> <coin>Bronze</coin> </coins> I can do this at a global level by saying all lists should be aliased to coins, but I have a lot of different lists and this won't work. Any ideas on how to

parse google geocode with xstream

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问题 I'm using Java and XStream to parse a google geocode request over http. My idea is to have an Address class with all the geocode attr's (ie. lat/long, city, provice/state etc) but I'm having problems parsing the xml with xstream. The google response is similar to this: <?xml version="1.0" encoding="UTF-8" ?> <kml xmlns="http://earth.google.com/kml/2.0"><Response> <name>98 St. Patrick St, Toronto</name> <Status> <code>200</code> <request>geocode</request> </Status> <Placemark id="p1"> <address

你知道这高效的12个Java精品库嘛？

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01. JUnit 第一个要说的当然是JUnit了，JUnit毕竟是Java圈目前最知名及常用的测试框架。JUnit之所以能够成为Java圈中最热门的测试库，是因为对于很多项目而言，单元测试是非常重要的。优点有很多比如，给开发者提供了简洁的图形界面，可以轻松地写出可重复测试的代码，允许并发同时执行，还允许开发者创建测试套件 (Test Suite) 来查看、检测整体的测试进度及测试期间发生的副作用等。 02. SLF4J SLF4J或Simple Logging Facade for Java，它为不同的框架提供了一个抽象概念，允许开发人员在部署时插入任何框架。它的功能在基于外观的简单日志API，并将客户端API与日志后端分开。通过向classpath中添加所需的绑定，可以发现其后端。由于客户端API和后端完全解耦，因此它可以集成到任何框架或现有的代码片段。 03. Log4j Log4j是Apache中的一个库，可用作日志工具。 Log4j恰好是其所在应用领域中最可靠的库，可以扩展到支持自定义组件配置。配置语法非常简单，支持XML、YAML 和 JSON。并提供对多个API的支持，最重要的是，它的工作速度相当惊人。 04. Google Guava Google Guava是Java编程的另一个受欢迎的Java核心库 Google

How to unmarshal Map using XStream

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问题 I cannot seem to be able to unmarshall a Map properly using XStream. I have the following code: Storage class public class Storage { @XStreamAsAttribute private String basedir; @XStreamAsAttribute private Map<String, Repository> repositories = new LinkedHashMap<String, Repository>(); ... } Repository class public class Repository { @XStreamAsAttribute private String name; @XStreamAsAttribute private String basedir; @XStreamAsAttribute private int policy; @XStreamAsAttribute private int layout

Variable initialization past Xstream

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问题 Consider the following declaration as part of SomeClass private Set<String> blah = new HashSet<String>(); Made in a class, which is later XStream xstream = new XStream(new JettisonMappedXmlDriver()); xstream.setMode(XStream.NO_REFERENCES); StringBuilder json = new StringBuilder(xstream.toXML(SomeClass)); rd = (SomeClass) xstream.fromXML(json.toString()); When i @Test assertTrue(rd.getBlah().size() == 0); I get an NPE on rd.getBlah() When I, instead of initializing up front, place

What happens if multiple converters can unmarshal xml?

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问题 Imean that there might be two or more XXXConverter extends ReflectionConverter that might return true here public boolean canConvert(Class aClass) for the same class 回答1: Only one converter will be used for a class. If you register multiple converters with the same priority, then the most recently registered one will be used. Take a look at the source for DefaultConverterLookup . 回答2: I guess they'd both convert it. But I guess the best answer would be to either look it up in the