xstream | 易学教程

How to add an XML namespace (xmlns) when serializing an object to XML

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问题 I'm serializing Objects to XML with the help of XStream. How do I tell XStream to insert an xmlns to the XML output of my object? As an example, I have this simple object I want to serialize: @XStreamAlias(value="domain") public class Domain { @XStreamAsAttribute private String type; private String os; (...) } How do I achieve exactly the following output with XStream? <domain type="kvm" xmlns:qemu="http://libvirt.org/schemas/domain/qemu/1.0"> <os>linux</os> </domain> 回答1: Alternatively, this

Can't add xstream 1.4.8 dependency to Android using gradle

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问题 I'm having difficulties with including xstream library to my Android gradle-based app. From what I've read in xstream documentation, it should work "out of the box". However, when I add dependency: compile 'com.thoughtworks.xstream:xstream:1.4.8' I get following exception during build process: * What went wrong: Execution failed for task ':app:transformClassesWithJarMergingForDebug'. > com.android.build.api.transform.TransformException: java.util.zip.ZipException: duplicate entry: org/xmlpull

XStream parse attributes and values at the same time

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问题 I have the following XML <search ver="3.0"> <loc id="ARBA0009" type="1">Buenos Aires, Argentina</loc> <loc id="BRXX1283" type="1">Buenos Aires, Brazil</loc> <loc id="ARDF0127" type="1">Aeroparque Buenos Aires, Argentina</loc> <loc id="MXJO0669" type="1">Concepcion De Buenos Aires, Mexico</loc> <loc id="MXPA1785" type="1">San Nicolas De Buenos Aires, Mexico</loc> <loc id="ARBA0005" type="1">Balcarce, Argentina</loc> <loc id="ARBA0008" type="1">Bragado, Argentina</loc> <loc id="ARBA0010" type=

Spring Batch, JdbcExecutionContextDao java.util.Map$Entry deserializer issue, xstream 1.4.1

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问题 I have a problem using Spring Batch 2.1.9: when i use jobExplorer.getJobExecution(jobExecutionId) , i find a problem when DAO has to deserialize a string like: {"map":[{"entry":{"string":"parsedComparingDate","date":"2014-03-08 23:00:00.0 UTC"}}]} from the BATCH_JOB_EXECUTION_CONTEXT table, using method JdbcJobExecutionDao.getJobExecution() . I know that spring batch uses xstream 1.3, but in my Pom, i have: spring-batch 2.1.9 ; xstream 1.4.1 (inherited from smooks); jettison 1.3.3 (inherited

Xstream: removing class attribute

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问题 How do I remove the class=”Something ” attributes in Xstream . I use Xstream with annotations 回答1: Indeed the problem is not as clearly phrased as it should. My guess is that you are using a non-standard collection or using a field of an interface type for which XStream needs to store the actual class. In the second case you can just use alias: xstream.alias("field name", Interface.class, ActualClassToUse.class); See http://markmail.org/message/gds63p3dnhpy3ef2 for more details. 回答2: I read

com.thoughtworks.xstream.converters.ConversionException

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问题 [EDITED] The project i'm working on is a 3 folder project in Java J2EE with servlets and Hibernate for the persistance. The structure is as follow: - Admin -> the main program with the beans and HTML/CSS - Jar -> with the jars, Hibernate tools and classes - War -> with the Servlets Between them, I use Xstream to share the classes and important info. I'm using Eclipse and Tomcat 7. Hope that with this all of you get the global idea. This what the Xstream debugger said: Caused by: com

微信公众号开发者模式介绍及接入

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Java公众号开发环境搭建需要准备的东西：一个微信公众号，参考：微信公众号申请及介绍内网穿透工具，参考：使用natapp开启内网穿透之旅数据交互编辑模式和开发模式的关系：编辑模式和开发模式是互斥的关系，也就是说，当我们使用开发模式时，编辑模式下的操作就会失效。反之，使用编辑模式时，开发模式下的操作就会失效，所以只能使用其中一个模式进行公众号的开发。开发模式下，公众号数据的交互流程：注：图中的微信公众号服务器，就是我们开发者所要开发的部分开发者模式接入微信公众平台相关技术文档地址如下：微信公众平台技术文档入门指引接入指南我们根据 “接入指南” 中的说明来完成公众平台的接入，但是我们跳过文档中的第一步，先来完成第二步的操作，即验证消息的确来自微信服务器。因为提交服务器配置信息时微信会对配置的URL发起调用，验证该服务器是否正常可用，所以我们得先把第二步完成，才能去完成第一步。既然是开发就得建工程了，所以在IDEA中创建一个SpringBoot工程，工程结构如下：先说明一点：当我们提交服务器配置信息后，微信服务器将发送GET请求到填写的服务器地址URL上，GET请求携带参数分别为signature、timestamp、nonce、echostr。开发者通过检验signature对请求进行校验，若确认此次GET请求来自微信服务器

Xstream Implicit Map As Attributes to Root Element

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问题 I am trying to find a solution to convert a map into root element attributes using XStream. I do not think this is possible but here is what I have tried to far. I created a custom converter and attached it to the root object, in the converter I then get access to the map that I am trying to convert into attributes, I iterate through the map and write the attirbute to the node, using writer.addAttribute(entry.getKey(), entry.getValue()); this does actually write the attributes to the root

get xml as string instead of class with xstream

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问题 I have xml something like <parent> <message> <type>15</type> </message> </parent> Instead of creating a message object inside parent object, I need to represent message just as a String . So , when I do parent.message , the output is <type> 15 </type> instead of a message object. 回答1: The idia is to build up the xml of message by processing the HierarchicalStreamReader . If you go down into <messsage> by calling reader.goDown() unfortunately reader.getValue() does not return the whole content

How can I get XStream to output Scala lists nicely? Can I write a custom converter?

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问题 This code: println(new XStream.toXML(List(1,2,3))) produces this XML: <scala.coloncolon serialization="custom"> <unserializable-parents/> <scala.coloncolon> <int>1</int> <int>2</int> <int>3</int> <scala.ListSerializeEnd/> </scala.coloncolon> </scala.coloncolon> Instead I'd like this: <list> <int>1</int> <int>2</int> <int>3</int> </list> Which would be similar to how the generic java collections get serialized. Whats the best way to do this? I've got most of the way there by implementing my