variable-initialization

问题 I'm curious to know the difference between declaring a variable, and initializing a variable. e.g. var example; // this is declaring var example = "hi" // initializing? Or just "adding a value"? I don't think I'm right there, but what exactly is the definition of each? Or do they basically mean the same thing? 回答1: Edit: @ThisClark said something in the comments, and I went to prove him wrong, and upon reading the spec some more I learned something: Here's an informative except from the

问题 Is there a nice way to stop the repetition of task from within the task itself when running in a ScheduledExecutorService? Lets say, I have the following task: Future<?> f = scheduledExecutor.scheduleAtFixedRate(new Runnable() { int count = 0; public void run() { System.out.println(count++); if (count == 10) { // ??? cancel self } } }, 1, 1, TimeUnit.SECONDS); From outside, it is easy to cancel via f.cancel(), but how can I stop the repetition at the specified place? (Passing the Future

问题 To the best of my knowledge, there are three ways to initialize a variable in C++. int x = 0; // C-like initialization int x (0); // Constructor initialization int x {0}; // Uniform initialization The uniform initialization was brought on for C++11 to provide a more uniform syntax for initializing different types of variables, which required different syntax in C++03. What are the differences between C-like, constructor, and uniform initialization? And should I always use the uniform