unroll

Spock Unroll seems to print something odd with boolean parameter

由 风格不统一 提交于 2020-05-17 05:49:09
问题 I just put this test method together: @Unroll def 'super start edit should be called if cell is not empty'( boolean empty ){ given: DueDateEditor editor = GroovySpy( DueDateEditor ){ isEmpty() >> empty } when: editor.startEdit() then: if( empty){ 0 * editor.callSuperStartEdit() } else { 1 * editor.callSuperStartEdit() } where: empty | _ true | _ false | _ } ... it works OK in terms of the two tests passing... but when you make it fail it's very odd: the output if the parameter empty is false

unroll loops in an AMD OpenCL kernel

由 断了今生、忘了曾经 提交于 2019-12-24 14:18:31
问题 I'm trying to assess the performance differences between OpenCL for AMD .I have kernel for hough transfrom in the kernel i have two #pragma unroll statements when run the kernel not produce any speedup kernel void hough_circle(read_only image2d_t imageIn, global int* in,const int w_hough,__global int * circle) { sampler_t sampler=CLK_NORMALIZED_COORDS_FALSE | CLK_ADDRESS_CLAMP_TO_EDGE | CLK_FILTER_NEAREST; int gid0 = get_global_id(0); int gid1 = get_global_id(1); uint4 pixel; int x0=0,y0=0,r;

Tell gcc to specifically unroll a loop

由 天大地大妈咪最大 提交于 2019-12-17 04:27:52
问题 How can I tell GCC to unroll a particular loop? I have used the CUDA SDK where loops can be unrolled manually using #pragma unroll . Is there a similar feature for gcc? I googled a bit but could not find anything. 回答1: GCC gives you a few different ways of handling this: Use #pragma directives , like #pragma GCC optimize ("string"...) , as seen in the GCC docs. Note that the pragma makes the optimizations global for the remaining functions. If you used #pragma push_options and pop_options

Efficient by-hand loop unrolling

由 て烟熏妆下的殇ゞ 提交于 2019-12-11 06:31:21
问题 I have this C code: for (k = 0; k < n_n; k++) { if (k == i || k == j) continue; dd=q2_vect[k]-q1_vect; d2=dd*dd; if (d2<0) { a=1; break; } } For compiler optimization reasons (on the SPE of the Cell processor), I need to unloop this by hand, so I tried: dd=q2_vect[0]-q1_vect; d2=dd*dd; if (d2<0)goto done; dd=q2_vect[1]-q1_vect; d2=dd*dd; if (d2<0)goto done; dd=q2_vect[2]-q1_vect; d2=dd*dd; if (d2<0)goto done; ..... ..... // end goto notdone; done: ok=0; notdone: ..... but I do not know how to

Why does the performance of my #pragma-unrolled loop degrade if the trip count is not constant?

由 半腔热情 提交于 2019-12-04 19:01:31
问题 I have following code using loop unrolling: #pragma unroll for (int i=0;i<n;i++) { .... } here if n is a defined constant, everything works fine. However, if n is a variable, performance dramatically reduced. I noticed roughly 3 times the instructions are issued and executed. I guess I am looking for a way to do loop unrolling at run time, may be that's just not feasible. 回答1: CUDA is a compiled language. Loop unrolling is a compiler optimization. Runtime loop unrolling would imply some sort

Why does the performance of my #pragma-unrolled loop degrade if the trip count is not constant?

由 别来无恙 提交于 2019-12-03 11:49:54
I have following code using loop unrolling: #pragma unroll for (int i=0;i<n;i++) { .... } here if n is a defined constant, everything works fine. However, if n is a variable, performance dramatically reduced. I noticed roughly 3 times the instructions are issued and executed. I guess I am looking for a way to do loop unrolling at run time, may be that's just not feasible. CUDA is a compiled language. Loop unrolling is a compiler optimization. Runtime loop unrolling would imply some sort of runtime interpreter or dynamic code generation. That clearly can't happen. It would make sense that the

Unlist a data frame by rows, not columns

由 馋奶兔 提交于 2019-11-26 14:45:30
问题 A relatively simple question, but the answer seems to have eluded me. Currently, I have a data frame which looks similar to this: 0 0 0 1 1 0 1 0 1 1 2 1 1 0 3 I'm trying to turn this into a single line of data, by rows. I used the unlist function, and it did what I wanted, but gave them to me by columns. It gave me this: 0,0,2,0,1,1,0,0,1,1,1,0,1,1,3 but what I want is this: 0,0,0,1,1,0,1,0,1,1,2,1,1,0,3 I apologize if this seems like a silly question, but I'm still a novice with R. Any help
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