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Getting OS Error when passing string to pathlib.Path in windows

由 拜拜、爱过 提交于 2019-12-24 07:29:31
问题 How to pass string to pathlib.Path in Python3. I am dynamically passing normal windows path in Path(). But it is throwing error. the snippet is as below: src = "C:\Documents\Newsletters\Summer2018.pdf" rsrc = r"C:\Documents\Newsletters\Summer2018.pdf" s = pathlib.Path(src) rs = pathlib.Path(rsrc) print(s.exists()) # throws error print(rs.exists()) # returns True I want to pass normal string to Path, instead off raw string. Is there anyway to pass normal string to Path and check for its

Getting OS Error when passing string to pathlib.Path in windows

由 筅森魡賤 提交于 2019-12-24 07:29:06
问题 How to pass string to pathlib.Path in Python3. I am dynamically passing normal windows path in Path(). But it is throwing error. the snippet is as below: src = "C:\Documents\Newsletters\Summer2018.pdf" rsrc = r"C:\Documents\Newsletters\Summer2018.pdf" s = pathlib.Path(src) rs = pathlib.Path(rsrc) print(s.exists()) # throws error print(rs.exists()) # returns True I want to pass normal string to Path, instead off raw string. Is there anyway to pass normal string to Path and check for its

matplotlib does not show my drawings although I call pyplot.show()

由 荒凉一梦 提交于 2019-11-26 10:05:25
Help required on matplotlib. Yes, I did not forget calling the pyplot.show(). $ ipython --pylab import matplotlib.pyplot as p p.plot(range(20), range(20)) It returns matplotlib.lines.Line2D at 0xade2b2c as the output. p.show() There is nothing to happen. No error message. No new window. Nothing. I install matplotlib by using pip and I didn't take any error messages. Details: I use, Ubuntu IPython v0.11 Python v2.6.6 matplotlib v1.0.1 If I set my backend to template in ~/.matplotlib/matplotlibrc , then I can reproduce your symptoms: ~/.matplotlib/matplotlibrc: # backend : GtkAgg backend :

matplotlib does not show my drawings although I call pyplot.show()

由 假如想象 提交于 2019-11-26 02:50:30
问题 Help required on matplotlib. Yes, I did not forget calling the pyplot.show(). $ ipython --pylab import matplotlib.pyplot as p p.plot(range(20), range(20)) It returns matplotlib.lines.Line2D at 0xade2b2c as the output. p.show() There is nothing to happen. No error message. No new window. Nothing. I install matplotlib by using pip and I didn\'t take any error messages. Details: I use, Ubuntu IPython v0.11 Python v2.6.6 matplotlib v1.0.1 回答1: If I set my backend to template in ~/.matplotlib
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