subsequence

Difference between subarray, subset & subsequence

女生的网名这么多〃 提交于 2019-11-30 01:35:11
I'm a bit confused between subarray, subsequence & subset if I have {1,2,3,4} then subsequence can be {1,2,4} OR {2,4} etc. So basically I can omit some elements but keep the order. subarray would be( say subarray of size 3) {1,2,3} {2,3,4} Then what would be the subset? I'm bit confused between these 3. Wilson In my opinion, if the given pattern is array, the so called subarray means contiguous subsequence . For example, if given {1, 2, 3, 4}, subarray can be {1, 2, 3} {2, 3, 4} etc. While the given pattern is a sequence, subsequence contain elements whose subscripts are increasing in the

Difference between subarray, subset & subsequence

与世无争的帅哥 提交于 2019-11-29 00:00:07
问题 I'm a bit confused between subarray, subsequence & subset if I have {1,2,3,4} then subsequence can be {1,2,4} OR {2,4} etc. So basically I can omit some elements but keep the order. subarray would be( say subarray of size 3) {1,2,3} {2,3,4} Then what would be the subset? I'm bit confused between these 3. 回答1: In my opinion, if the given pattern is array, the so called subarray means contiguous subsequence . For example, if given {1, 2, 3, 4}, subarray can be {1, 2, 3} {2, 3, 4} etc. While the

What is the difference between String.subString() and String.subSequence()

一世执手 提交于 2019-11-28 22:32:35
问题 String.subSequence() has the following javadoc: Returns a new character sequence that is a subsequence of this sequence. An invocation of this method of the form str.subSequence(begin, end) behaves in exactly the same way as the invocation str.substring(begin, end) This method is defined so that the String class can implement the CharSequence interface. Can anyone explain? 回答1: Using str.subSequence(begin, end) returns a CharSequence which is a read-only form of the string represented as a

Number of all longest increasing subsequences

时光怂恿深爱的人放手 提交于 2019-11-27 18:12:53
I'm practicing algorithms and one of my tasks is to count the number of all longest increasing sub-sequences for given 0 < n <= 10^6 numbers. Solution O(n^2) is not an option. I have already implemented finding a LIS and its length ( LIS Algorithm ), but this algorithm switches numbers to the lowest possible. Therefore, it's impossible to determine if sub-sequences with a previous number (the bigger one) would be able to achieve the longest length, otherwise I could just count those switches, I guess. Any ideas how to get this in about O(nlogn) ? I know that it should be solved using dynamic

Number of all longest increasing subsequences

可紊 提交于 2019-11-27 04:15:52
问题 I'm practicing algorithms and one of my tasks is to count the number of all longest increasing sub-sequences for given 0 < n <= 10^6 numbers. Solution O(n^2) is not an option. I have already implemented finding a LIS and its length (LIS Algorithm), but this algorithm switches numbers to the lowest possible. Therefore, it's impossible to determine if sub-sequences with a previous number (the bigger one) would be able to achieve the longest length, otherwise I could just count those switches, I