subsequence

Assuming my table is WITH `sample_project.sample_dataset.table` AS ( SELECT 'user1' user, 2 sequence, 'T1' ts UNION ALL SELECT 'user1', 2, 'T2' UNION ALL SELECT 'user1', 1, 'T3' UNION ALL SELECT 'user1', 1, 'T4' UNION ALL SELECT 'user1', 3, 'T5' UNION ALL SELECT 'user1', 2, 'T6' UNION ALL SELECT 'user1', 3, 'T7' UNION ALL SELECT 'user1', 3, 'T8' ) Can I find Subsequence of Integers available in sequence column without using STRING_AGG and REGEX OR JOIN operations ? This is to make query more efficient. A subsequence is a part of String. For example consider String "banana", A sample

Given an array which contains N different integers, find the longest subsequence which satisfies: the start element of the subsequence is the smallest of the subsequence. the end element of the subsequence is the largest of the subsequence. Eg: 8,1,9,4,7. The answer is 1,4,7. 2,6,5,4,9,8. The answer is 2,6,5,4,9 or 2,6,5,4,8. Here is a O(N^2) algorithm: Let X be the array of numbers. Iterate over X . Suppose we are at index i . Let Y be the array where Y[j] is the number of elements in (j, i] which are smaller than X[j]. Let z be the number of elements in [j, i] which are smaller than X[i]. If

I'v a sequence of integer number [A1, A2, A3.....AN] I'm trying to count all sub-sequences which contain at most K unique numbers. For Example: Given sequence:: [2, 3, 3, 7, 5] and K = 3 All sub-sequences are: [], [2],[3],[3],[7],[5], [2, 3],[2, 3],[2, 7],[2, 5],[3, 3],[3, 7],[3, 5],[3, 7],[3, 5],[7, 5], [2, 3, 3],[2, 3, 7],[2, 3, 5],[2, 3, 7],[2, 3, 5],[2, 7, 5],[3, 3, 7],[3, 3, 5],[3, 7, 5],[3, 7, 5], [2, 3, 3, 7],[2, 3, 3, 5],[2, 3, 7, 5],[2, 3, 7, 5],[3, 3, 7, 5], [2, 3, 3, 7, 5] I need all sub-sequences (only for counting) that have unique elements. ✅ Counted sub-sequences are: [], [2],[3

I'm looking to explore different algorithms, both recursive and dynamic programming, that checks if one arrayA is a subsequence of arrayB. For example, arrayA = [1, 2, 3] arrayB = [5, 6, 1, 7, 2, 9, 3] thus, arrayA is indeed a subsequence of arrayB. I've tried a few different searches, but all I can seem to find is algorithms to compute the longest increasing subsequence. Since you must match all elements of arrayA to some elements of arrayB , you never need to backtrack . In other words, if there are two candidates in arrayB to match an element of arrayA , you can pick the earliest one, and

I was wondering what would be the best way to implement this. Can't think of a good way to save what information that needs to be saved like the index and the number of values and finally the actual number that get's repeated public class testing { public static void main(String[] args) { ArrayList<Integer> numbers = new ArrayList<Integer>(); Scanner in = new Scanner(System.in); Integer a =0; Integer value = 0; Integer num = 0; boolean loop = true; //getting the string information while(loop) { System.out.println("Enter a series of numbers, 0 to stop"); Integer n = in.nextInt(); if(n.equals(0)

String.subSequence() has the following javadoc: Returns a new character sequence that is a subsequence of this sequence. An invocation of this method of the form str.subSequence(begin, end) behaves in exactly the same way as the invocation str.substring(begin, end) This method is defined so that the String class can implement the CharSequence interface. Can anyone explain? Sam Using str.subSequence(begin, end) returns a CharSequence which is a read-only form of the string represented as a sequence of chars. For example: String string = "Hello"; CharSequence subSequence = s.subSequence(0, 5);