string-length

问题 I have written code for determining the nth longest string in an array of strings. Below I have test cases listed from the Codewars kata. Instructions : Implement the function longest(array,n) where you will be given an array of strings and then return the nth longest string in that array. e.g. arr = ['Hello','World','Codewars','Katas'] n = 3; should return 'World' because 'Codewars' length = 8 , 'Hello' length = 5, so that is the 2nd longest word and then 'World' (although also word length

问题 I came across this code in a javascript open source project. validator.isLength = function (str, min, max) // match surrogate pairs in string or declare an empty array if none found in string var surrogatePairs = str.match(/[\uD800-\uDBFF][\uDC00-\uDFFF]/g) || []; // subtract the surrogate pairs string length from main string length var len = str.length - surrogatePairs.length; // now compare string length with min and max ... also make sure max is defined(in other words, max param is

问题 I came across this code in a javascript open source project. validator.isLength = function (str, min, max) // match surrogate pairs in string or declare an empty array if none found in string var surrogatePairs = str.match(/[\uD800-\uDBFF][\uDC00-\uDFFF]/g) || []; // subtract the surrogate pairs string length from main string length var len = str.length - surrogatePairs.length; // now compare string length with min and max ... also make sure max is defined(in other words, max param is

问题 This question already has answers here : Adding a DataFrame column with len() of another column's values (2 answers) Closed 3 years ago . I have a pandas dataframe. df = pd.DataFrame(['Donald Dump','Make America Great Again!','Donald Shrimp'], columns=['text']) What I like to have is another column in Dataframe which has the length of the strings in the 'text' column. For above example, it would be text text_length 0 Donald Dump 11 1 Make America Great Again! 25 2 Donald Shrimp 13 I know I

问题 This question already has answers here : Adding a DataFrame column with len() of another column's values (2 answers) Closed 3 years ago . I have a pandas dataframe. df = pd.DataFrame(['Donald Dump','Make America Great Again!','Donald Shrimp'], columns=['text']) What I like to have is another column in Dataframe which has the length of the strings in the 'text' column. For above example, it would be text text_length 0 Donald Dump 11 1 Make America Great Again! 25 2 Donald Shrimp 13 I know I

问题 So I input strings into an array mydata[10][81] while ((ct<=10) && gets(mydata[ct]) != NULL && (mydata[ct++][0] != '\0')) I then use a for loop to create a second array of pointers for (i=0;i<11;i++){ ptstr[i] = mydata[i]; } This is where I get stuck I know I need to use strlen somehow, but I can't even conceive of how to get the length of a pointer and then re-assign that pointer a new position based on a third additional value of length Hopefully that makes sense, I'm so lost on how to do

问题 I was wondering if there is an already made function in R base package that can sort a vector of strings taking into consideration the length of each element and then of course the lexicographical order. For instance after a sort call on some vector holding age groups you would have: v <- c("00-04", "05-09", "10-14", "100-104", "105-109", "110-114", "15-19", "20-24"..etc) whereas I would like to have: v <- c("00-04", "05-09", "10-14", "15-19", "20-24"..etc.. "100-104", "105-109", "110-114")

问题 I have been tasked with writing a Fortran 95 program that will read character input from a file, and then (to start with) simply spit it back out again. The tricky part is that these lines of input are of varying length (no maximum length given) and there can be any number of lines within the file. I've used do read( 1, *, iostat = IO ) DNA ! reads to EOF -- GOOD!! if ( IO < 0 ) exit ! if EOF is reached, exit do I = I + 1 NumRec = I ! used later for total no. of records allocate( Seq(I) ) Seq

问题 I am trying to get the length of a string but i am getting the wrong value, it is saying that it is only 4 characters long. Why is this? am i using sizeof() correctly? #include <stdio.h> int main(void) { char *s; int len; s = "hello world"; len = sizeof(s); printf("%d\n", len); } 回答1: The sizeof operator is returning the size of the pointer. If you want the length of a string, use the strlen function. Even if you had an array (e.g. char s[] = "hello world" ) the sizeof operator would return

问题 i am having a hard time learning how to loop through a string in Golang to do some stuff(separate words than contain vowels). I wrote this code snippet https://play.golang.org/p/zgDtOyq6qf Here is the error : panic: runtime error: index out of range goroutine 1 [running]: panic(0x1045a0, 0x1040a010) /usr/local/go/src/runtime/panic.go:500 +0x720 main.myFunc(0x114130, 0x4, 0x0, 0x0, 0x0, 0x3ba3) /tmp/sandbox960520145/main.go:19 +0x1a0 main.main() /tmp/sandbox960520145/main.go:10 +0x40 I