sql-like

问题 for MySQL I'm using this and works very well with UTF-8. SELECT * FROM cat.item_list WHERE CONVERT(item_name USING utf8) LIKE (:searchString) I've tried same query with sqlite but it doesn't work. What should I do for UTF-8 SQLite3 search query? (with LIKE) my current sqlite3 qry (which doesn't work with UTF-8 charsets): SELECT * FROM item_list WHERE item_name LIKE '%$safeName%' 回答1: Try this: $query = "SELECT * FROM item_list WHERE item_name LIKE '%" . $safeName . "%'"; 回答2: I solved like

问题 I'm having an issue here with my WHERE LIKE statement. Ideally, I want to be able to search for multiple terms (or just 1 or the other). Right now, for testing purposes, I have this separated in my test form where I choose what type of function I'm running. Purpose : Please ignore the update function for the moment (I'm sure it's a mess like the rest but I haven't finished up there yet). Still trying to finish the dFind() function. The purpose of this testing is so that I can build a data

问题 I'm having an issue here with my WHERE LIKE statement. Ideally, I want to be able to search for multiple terms (or just 1 or the other). Right now, for testing purposes, I have this separated in my test form where I choose what type of function I'm running. Purpose : Please ignore the update function for the moment (I'm sure it's a mess like the rest but I haven't finished up there yet). Still trying to finish the dFind() function. The purpose of this testing is so that I can build a data

问题 We are looking for mysql query which provide result exactly like '%%' query but using full text search MATCH AGAINST For example Select id,name from table where jobtitle like '%java software engineer in google%' It gives all rows which contain line java software engineer in google But if we use following mysql query then it gives a different result Select id,name from table where MATCH(jobtitle) AGAINST ('+java software engineer in google' IN BOOLEAN MODE) It gives rows which contain any word

问题 I need to insert a string into an Sql Command search.CommandText = "SELECT * FROM Contacts WHERE Name like ' + @person + % + '"; What it the right way of using LIKE in a command? 回答1: Should be: SELECT * FROM Contacts WHERE Name like @person + '%' @person is a parameter - you don't need single quotes around it. You only need to concatenate it with % , which should have quotes. Keep in mind: You could have kept it "SELECT * FROM Contacts WHERE Name like @person" , and have the parameter value

问题 I'm trying to retrieve all columns that start with any non alpha characters in SQlite but can't seem to get it working. I've currently got this code, but it returns every row: SELECT * FROM TestTable WHERE TestNames NOT LIKE '[A-z]%' Is there a way to retrieve all rows where the first character of TestNames are not part of the alphabet? 回答1: Are you going first character only? select * from TestTable WHERE substr(TestNames,1) NOT LIKE '%[^a-zA-Z]%' The substr function (can also be called as

问题 I want to perform a simple search using the SQL LIKE function. Unfortunately for some reason , it doesn't seem to be working. Below is my code. private void gvbind() { connection.Open(); string sql = ""; if (txtSearch.Text.Trim() == "") { sql = "SELECT a.cname,[bid],b.[bname],b.[baddress],b.[bcity],b.[bstate],b.[bpostcode],b.[bphone],b.[bfax],b.[bemail] FROM [CLIENT] a INNER JOIN [BRANCH] b ON a.clientID=b.clientID ORDER BY a.[clientID]"; } else { sql = "SELECT a.cname,[bid],b.[bname],b.

问题 Is there any way to make following query Work? declare @t nvarchar(20) set @t='حس' SELECT [perno] ,[pName] FROM [dbo].[People] Where [pName] like N''+@t +'%' I cann't use like this: Where [pName] like N'حس%' Or using an stored procedure : ALTER PROCEDURE [dbo].[aTest] (@t nvarchar(20)) AS BEGIN SELECT [perno] ,[pName] FROM [dbo].[People] WHERE ([People].[pName] LIKE N'' +@t + '%') END 回答1: You don't need to use N prefix in the WHERE clause since your variable is already nvarchar , and you are

问题 my question is that currently if i want to query for multiple wildcarded values. I need to do something like this. select customername from customers where customername like '%smith' or customername like '%potter' or customer name like '%harris' or customername like '%williams'; So I wanna ask from the experts, is there any easier way to do this? Regards, Sanjan 回答1: Create a table of your 100 names select customername from customers c inner join customersames cn on(c.customernamename like '%

问题 There should be a break after every row LIKE 'A%' when find next records of LIKE 'B%' . $stmt = $con->prepare("SELECT * FROM fistevent WHERE Event_Id=? AND TicketType=? AND row_name REGEXP '^[A-Z]' ORDER BY row_name ASC"); $stmt->bind_param("ss", $_POST['EventId'],$_POST['TicketType']); $stmt->execute(); $result = $stmt->get_result(); $numRows = $result->num_rows; if($numRows > 0) { echo ' <div class="register">'; while($r = $result->fetch_assoc()) { $EvntId = $r['Event_Id']; $RowName = $r[