问题
We are looking for mysql query which provide result exactly like '%%' query but using full text search MATCH AGAINST
For example
Select id,name from table where jobtitle like '%java software engineer in google%'
It gives all rows which contain line java software engineer in google
But if we use following mysql query then it gives a different result
Select id,name from table
where MATCH(jobtitle) AGAINST ('+java software engineer in google' IN BOOLEAN MODE)
It gives rows which contain any word of from java software engineer in google
I want the exact output which comes from using like '%java software engineer in google%' query.
回答1:
As MySQL documentation on Boolean fulltext search indicates (bolding is mine):
The boolean full-text search capability supports the following operators: [...]
"
A phrase that is enclosed within double quote (“"”) characters matches only rows that contain the phrase literally, as it was typed. The full-text engine splits the phrase into words and performs a search in the FULLTEXT index for the words. Nonword characters need not be matched exactly: Phrase searching requires only that matches contain exactly the same words as the phrase and in the same order. For example, "test phrase" matches "test, phrase".
If the phrase contains no words that are in the index, the result is empty. The words might not be in the index because of a combination of factors: if they do not exist in the text, are stopwords, or are shorter than the minimum length of indexed words.
So, use the " operator:
Select id,name from table
where MATCH(jobtitle) AGAINST ('"java software engineer in google"' IN BOOLEAN MODE)
The bolded section contains the caveat: the results may be slightly different because of the nature of the fulltext index.
来源：https://stackoverflow.com/questions/39467443/full-text-search-result-similar-to-mysql-like-query