simultaneous-calls

How to make a call to multiple clients and how to add one of them into conference call in twilio

江枫思渺然 提交于 2020-05-17 05:56:43
问题 Client A make a calls to Client B,C,D,E simultaneously if one of them picks a call we have to end up a call to remaining of them.later we if we want to add Client X we can add them into a conference call.like this i have to do.but the thing is it is adding all clients who picks the call they are come to the call.for example if Client B,C,D,E picks call they all are coming into the call with a Client A.and if i hangup the call it is not hanging up to the all clients. this is my code what id

Web service not handling multiple simultaneous request from same application with proxy class

大城市里の小女人 提交于 2020-01-13 19:10:48
问题 I have an application scheduling multiple tasks which are calling different web services, some the same web service but different method. Each task is executed in an interval and each task is running in its own thread. To obtain reference to the webservice I have a wsdl.exe generated proxy class which is instantiated inside each of the tasks and allways disposed. However when running the application, the tasks are actually waiting for eachother at the service requests, web service doesnt

Web service not handling multiple simultaneous request from same application with proxy class

故事扮演 提交于 2020-01-13 19:10:28
问题 I have an application scheduling multiple tasks which are calling different web services, some the same web service but different method. Each task is executed in an interval and each task is running in its own thread. To obtain reference to the webservice I have a wsdl.exe generated proxy class which is instantiated inside each of the tasks and allways disposed. However when running the application, the tasks are actually waiting for eachother at the service requests, web service doesnt

Web service not handling multiple simultaneous request from same application with proxy class

随声附和 提交于 2020-01-13 19:09:22
问题 I have an application scheduling multiple tasks which are calling different web services, some the same web service but different method. Each task is executed in an interval and each task is running in its own thread. To obtain reference to the webservice I have a wsdl.exe generated proxy class which is instantiated inside each of the tasks and allways disposed. However when running the application, the tasks are actually waiting for eachother at the service requests, web service doesnt

JQuery - When calling a function multiple times in a row, why only the callback of the last call is executed properly?

╄→尐↘猪︶ㄣ 提交于 2019-12-10 21:35:40
问题 There is a function that triggers a callback when finished; I call this function 2 or 3 times consecutively; Only the callback of the last call does what was expected; The following description and code exemplifies the true scenario. I have three pairs of divs. I need to toggle one div of each pair and change the state of the remaining visible divs when it's pair is no more visible. Then, I made a function to hide a div and change the background color of another one. I did this because I'd

Close Spinners dropdown when two among all in a groupview are clicked simultaneously

孤街浪徒 提交于 2019-12-08 07:37:53
问题 I have several drop down (Spinners) in my Android ViewGroup. When I try to click two of them simultaneously, They both get open. There is however by default behavior in Android that if a spinner is 'opened' and you do a click somewhere, it gets closed: Nothing Selected in the listener gets called on Item Selected Listener. I want, on simultaneous click over both of the Spinners, none of them should get opened. However on single selection (one Spinner only) it should work correctly. 回答1: Say

Web service not handling multiple simultaneous request from same application with proxy class

感情迁移 提交于 2019-12-06 07:21:49
I have an application scheduling multiple tasks which are calling different web services, some the same web service but different method. Each task is executed in an interval and each task is running in its own thread. To obtain reference to the webservice I have a wsdl.exe generated proxy class which is instantiated inside each of the tasks and allways disposed. However when running the application, the tasks are actually waiting for eachother at the service requests, web service doesnt process the service request from task y before its done processing request from task x (I can see this

Send Simultaneous Requests python (all at once)

六眼飞鱼酱① 提交于 2019-12-01 05:13:41
问题 I'm trying to create a script that send's over 1000 requests to one page at the same time. But requests library with threading (1000) threads. Seems to be doing to first 50 or so requests all within 1 second, whereas the other 9950 are taking considerably longer. I measured it like this. def print_to_cmd(strinng): queueLock.acquire() print strinng queueLock.release() start = time.time() resp = requests.get('http://test.net/', headers=header) end = time.time() print_to_cmd(str(end-start)) I'm

Python Multiple users append to the same file at the same time

a 夏天 提交于 2019-11-30 10:58:26
问题 I'm working on a python script that will be accessed via the web, so there will be multiple users trying to append to the same file at the same time. My worry is that this might cause a race condition where if multiple users wrote to the same file at the same time and it just might corrupt the file. For example: #!/usr/bin/env python g = open("/somepath/somefile.txt", "a") new_entry = "foobar" g.write(new_entry) g.close Will I have to use a lockfile for this as this operation looks risky. 回答1

Python Multiple users append to the same file at the same time

浪子不回头ぞ 提交于 2019-11-29 22:21:19
I'm working on a python script that will be accessed via the web, so there will be multiple users trying to append to the same file at the same time. My worry is that this might cause a race condition where if multiple users wrote to the same file at the same time and it just might corrupt the file. For example: #!/usr/bin/env python g = open("/somepath/somefile.txt", "a") new_entry = "foobar" g.write(new_entry) g.close Will I have to use a lockfile for this as this operation looks risky. phihag You can use file locking : import fcntl new_entry = "foobar" with open("/somepath/somefile.txt", "a