shift

Shell shift procedure - What is this?

南楼画角 提交于 2019-12-09 04:37:44
问题 In shell we have the command shift, but i saw on some example its giving shift 3 Why there is a number after shift ? and what its about ? what it does ? Example: echo “arg1= $1 arg2=$2 arg3=$3” shift echo “arg1= $1 arg2=$2 arg3=$3” shift echo “arg1= $1 arg2=$2 arg3=$3” shift echo “arg1= $1 arg2=$2 arg3=$3” shift The output will be: arg1= 1 arg2=2 arg3=3 arg1= 2 arg2=3 arg3= arg1= 3 arg2= arg3= arg1= arg2= arg3= But when i add that, it doesn't display it correctly. 回答1: Take a look at the man

How to Shift an array circularly on VBA [closed]

≯℡__Kan透↙ 提交于 2019-12-08 15:40:03
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I have the array (1,2,3) and I would like to do a circular shift in order to obtain for example (3,1,2) or (2,3,1). In Matlab I know how to do that using the following code: Y = circshift(A,K) Can u please help me with this task? I'd appreciate any sample codes... 回答1: Code: Private Function RotateArrayRight

How to shift array elements

我们两清 提交于 2019-12-08 08:59:16
问题 I have an array of n = 32 items with positive and negative values. First n/2 elements are positive and sorted by value and second n/2 elements are negative and sorted by value as well. I would like to sort the whole array by value, starting from the smallest negative value to biggest positive value which means if there are 32 elements the first 16 (n/2) sorted elements should contain the values of second 16 elements of the original array and the second 16 elements of the sorted array should

Converting 8 byte char array into long

前提是你 提交于 2019-12-08 06:56:31
问题 How do we convert 8 byte char array into long since << does not work for type long? #define word_size 8 long num = 0; char a[word_size] = "\x88\x99\xaa\x0bb\xcc\xdd\xee\xff"; for (i=0; i < word_size;i++) { a[(word_size-1) - i] |= (num << (8*(word_size - i - 1))) & 0xFF; } printf("%lx\n", num); 回答1: The following code is more efficient: unsigned char[word_size] = ...; int64_t num = 0; for ( int i = 0 ; i < sizeof(a) ; i++ ) num = (num << 8) | a[i]; This assumes big endian (highest order byte

Bitshifting in C++ producing the wrong answer

冷暖自知 提交于 2019-12-07 04:56:00
问题 I tried running the following code code: char c = (2 << 7) >> 7 which should return 0 because 2 has this binary representation as a char : 0 0 0 0 0 0 1 0 After 7 shifts left, we get 0 0 0 0 0 0 0 0 Then, after seven shifts right, we get 0 0 0 0 0 0 0 0 However, I'm getting the result as 2, not 0. The compiler says that 2 << 7 is 256, but it's a char and so it shouldn't be 256. I understand that the 2 << 7 will be calculated as int s and the answer will be put into c so 256 >> 7 is 2. I tried

Rotate left verilog case

寵の児 提交于 2019-12-06 16:28:14
问题 My task is to write a 16 bit ALU in verilog. I found difficulties when I do the part that needs to rotate the operand and doing the 2's complement addition and subtraction. I know how to work that out by paper and pencil but i cant figure out ways to do it in Verilog. for example: A is denoted as a15 a14 a13 a12 a11 a10 a9 a8 a7 a6 a5 a4 a3 a2 a1 a0 if i am going to rotate 4 bits, the answer would be a11 a10 a9 a8 a7 a6 a5 a4 a3 a2 a1 a0 a15 a14 a13 a12 i tried concatenation but it turns out

How to shift a std_logic_vector by std_logic_vector using concatenation

扶醉桌前 提交于 2019-12-06 10:44:34
问题 Say I have 2 std_logic_vectors: inputA : std_logic_vector(31 downto 0) inputB: std_logic_vector(31 downto 0) How do I shift inputA by inputB using concatenation? I know how to shift left or right by 1 place but can't figure out how to shift N places to the right (or left). Note: this is a clockless circuit, and can't use standard vhdl shift operators. Other techniques or ideas other than concatenation would be appreciated as well. 回答1: I prefer wjl's approach, but given you asked specifically

Shifting 2D array Verilog

我的梦境 提交于 2019-12-06 03:17:47
问题 I dont know what doesnt work on the following code, but it wont synthesize: reg [7:0] FIFO [0:8]; always@(posedge clk) begin if(wr & !rd & !full) begin FIFO[0:8] <= {data_in, FIFO[1:8]}; end end I tried to index the FIFO other ways too, but nothing works. Found this topic on a Xilinx forum but I just cant figue out what he wanted to tell with that. Here is the link: http://forums.xilinx.com/t5/General-Technical-Discussion/2-dimensional-array-problem-in-Verilog/td-p/42368 thanks 回答1: You have

SHift-click jqgrid multiselect missing last row

心已入冬 提交于 2019-12-05 16:12:15
I adopted the code from this post and made this fiddle . Try clicking the first row, then shift-clicking the last row. If you notice this code does very well, except the last row, the row that you click on, does not get selected. I have been scratching my head on this one. Can anyone help me alter the code so that the multiselect selects the last row too? Thanks! try replacing this: if ((shouldSelectRow = id == startID || shouldSelectRow)) { with this: if ((shouldSelectRow = id == startID || shouldSelectRow) && (id != rowid)){ Oleg I agree with Michael Gendin that you should not select the row

Shuffle a List in Scala [duplicate]

夙愿已清 提交于 2019-12-05 10:46:44
问题 This question already has an answer here : Scala ListBuffer (or equivalent) shuffle (1 answer) Closed 3 years ago . I have question to for shuffle list in scala using scala.util.Random . For example I have val a = cyan val b = magenta val c = yellow val d = key val color = Random.shuffle.List(a,b,c,d).toString //but it doesn't work ;( so I want the val color to be random order of val a, b, c and d . 回答1: User Scala's Random class method shuffle: scala.util.Random.shuffle(List(a,b,c,d)) 来源: