sh

问题 The scenario I have a file server that acts as a master storage for the files to sync and I have several clients that have a local copy of the master storage. Each client may alter files from the master storage, add new ones or delete existing ones. I would like all of them to stay in sync as good as possible by regularly performing a sync operation, yet the only tool I have available everywhere for that is rsync and I can only run script code on the clients, not on the server. The problem

问题 The bounty expires in 6 days . Answers to this question are eligible for a +50 reputation bounty. Robert Pollak wants to draw more attention to this question: With your help, I should be able to modify a current gitk version such that it uses --find-copies-harder to display the origin of copied files. In command line Git, the show , diff and log commands have got an option to --find-copies-harder . Is there a way I can tell (or patch) gitk to use this, too? I need this from time to time, and

问题 The bounty expires in 6 days . Answers to this question are eligible for a +50 reputation bounty. Robert Pollak wants to draw more attention to this question: With your help, I should be able to modify a current gitk version such that it uses --find-copies-harder to display the origin of copied files. In command line Git, the show , diff and log commands have got an option to --find-copies-harder . Is there a way I can tell (or patch) gitk to use this, too? I need this from time to time, and

问题 Imagine a path like this: /a/b/c/d/e/... Where ... could be any number of levels further deep, i.e., I don't know, ahead of time, whether there will be 2, 3, or 13 more level deep. How can I, using a FreeBSD shell, e.g., /bin/sh , extract the first "N" parts of this path? e.g., first 4 levels, so that I would get /a/b/c/d ? 回答1: You can use cut : s='/a/b/c/d/e/f/g/h/i/j/k' echo "$s" | cut -d/ -f1-5 /a/b/c/d Or if you are using BASH then you can use shell array: IFS=/ arr=($s) Then print

问题 Imagine a path like this: /a/b/c/d/e/... Where ... could be any number of levels further deep, i.e., I don't know, ahead of time, whether there will be 2, 3, or 13 more level deep. How can I, using a FreeBSD shell, e.g., /bin/sh , extract the first "N" parts of this path? e.g., first 4 levels, so that I would get /a/b/c/d ? 回答1: You can use cut : s='/a/b/c/d/e/f/g/h/i/j/k' echo "$s" | cut -d/ -f1-5 /a/b/c/d Or if you are using BASH then you can use shell array: IFS=/ arr=($s) Then print

来源： https://stackoverflow.com/questions/64123085/does-variable-store-the-command-or-the-result-of-the-command-in-posix-sh

来源： https://stackoverflow.com/questions/46262511/how-to-use-sdkman-to-install-packages-from-within-scripts

来源： https://stackoverflow.com/questions/46262511/how-to-use-sdkman-to-install-packages-from-within-scripts

来源： https://stackoverflow.com/questions/30607569/how-can-i-run-a-docker-container-and-commit-the-changes-once-a-script-completes

来源： https://stackoverflow.com/questions/30607569/how-can-i-run-a-docker-container-and-commit-the-changes-once-a-script-completes