seq

问题 We have time series data in which repeated observations were measured for several subjects. I would like to calculate the number of occasions in which the variable positive == 1 occurs for each subject (variable id ). A second aim is to identify the maximum length of these runs of consecutive observations in which positive == 1 . For each subject there are likely to be multiple runs within the study period. Rather than calculating the maximum number of consecutive positive observations per

问题 I am trying to sample between a range of values as part of a larger loop in R. As the loop progresses to each row j , I want to sample a number between the value given in the start column and the value given in the end column, placing that value in the sampled column for that row. The results should look something like this: ID start end sampled a 25 67 44 b 36 97 67 c 23 85 77 d 15 67 52 e 21 52 41 f 43 72 66 g 39 55 49 h 27 62 35 i 11 99 17 j 21 89 66 k 28 65 48 l 44 58 48 m 16 77 22 n 25

问题 I am trying to sample between a range of values as part of a larger loop in R. As the loop progresses to each row j , I want to sample a number between the value given in the start column and the value given in the end column, placing that value in the sampled column for that row. The results should look something like this: ID start end sampled a 25 67 44 b 36 97 67 c 23 85 77 d 15 67 52 e 21 52 41 f 43 72 66 g 39 55 49 h 27 62 35 i 11 99 17 j 21 89 66 k 28 65 48 l 44 58 48 m 16 77 22 n 25

问题 I'm an R newbie and probably the solution for my problem is very simple but it's out of my reach for now... I would like to compare rows in a data frame by columns. The data in each column is a letter (nucleotide base): seq1 A C T G T seq2 A C G G G seq3 A G G C A ... I'd like to compare all rows in the data set with each other by column. The result I would like to obtain is simple 1 or 0 for TRUE and FALSE in the comparison, written in a form of table as well. So it would look like this:

问题 If I have the following class public class Customer { public string Name; } and then have the following log command in Serilog Log.Logger = new LoggerConfiguration() .WriteTo.Console() .WriteTo.Seq("http://localhost:5341") .CreateLogger(); var item = new Customer(); item.Name = "John"; Serilog.Log.Information("Customer {@item}", item); The log just displays in Seq as Customer {} If I change the Name field to a property it works but I would prefer not to do that at this stage. Is there any way

问题 If I have the following class public class Customer { public string Name; } and then have the following log command in Serilog Log.Logger = new LoggerConfiguration() .WriteTo.Console() .WriteTo.Seq("http://localhost:5341") .CreateLogger(); var item = new Customer(); item.Name = "John"; Serilog.Log.Information("Customer {@item}", item); The log just displays in Seq as Customer {} If I change the Name field to a property it works but I would prefer not to do that at this stage. Is there any way

问题 I can't seem to find an elegant solution to finding ranges. For me, it would come down to this: > seq(1:10) [1] 1 2 3 4 5 6 7 8 9 10 I would like to get the reverse: function(c(1,2,3,4,5,6,7,8,9,10)) result 1:10 Real world problem is that I have 1200 indices, some are 0, some are 1: c(0,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0,1,0,0,1,1,1,1,1,1,0,0,0,0,1,1,1,1,1) And I would like the ranges/coordinates within the vector for each set of 0s and 1s. 回答1: Will this simple solution work? > rev(seq(1:10)) [1]

问题 In bash I need to run a script that loops from i=1 to i=99999999 but it always run out of memory. Is there any workaround? or is there a max value for i? first=1 last=99999999 randomString="CXCXQOOPSOIS" for val in $( seq $first $last ) do padVal=$( printf "%010d\n" $val ) hash=$( echo -n $randomString$padVal | md5sum ) if [[ "$hash" =~ ^000000) ]]; then echo "Number: $val" >> log_000000 echo "$val added to log - please check." fi done 回答1: bash provides C-like syntax for loop: first=1 last

问题 I'm trying to write a max function that operates on Seq Int . It should return the index with maximal value . Here is what I have: (declare-fun max ((Seq Int)) Int) (assert (forall ((A (Seq Int))) (=> (> (seq.len A) 0) (and (<= 0 (max A)) (< (max A) (seq.len A)) (forall ((i Int)) (=> (and (<= 0 i) (< i (seq.len A))) (<= (seq.nth A i) (seq.nth A (max A)))))))) ) (assert (= (max (seq.++ (seq.unit 8) (seq.unit 3))) 0)) ;(assert (= (max (seq.++ (seq.unit 8) (seq.unit 3))) 1)) (check-sat) When I

问题 I am trying to accomplish two things. First if I have a vector 1:5 I want to get a matrix (or two vectors) indicating the unique combinations of these elements including twice the same number but excluding repetitions. Right now I can do this using a matrix: foo <- matrix(1:5,5,5) cbind(foo[upper.tri(foo,diag=TRUE)],foo[lower.tri(foo,diag=TRUE)]) [,1] [,2] [1,] 1 1 [2,] 1 2 [3,] 2 3 [4,] 1 4 [5,] 2 5 [6,] 3 2 [7,] 1 3 [8,] 2 4 [9,] 3 5 [10,] 4 3 [11,] 1 4 [12,] 2 5 [13,] 3 4 [14,] 4 5 [15,] 5